PLEASE HELP!!!

For the class of 2013's prom Norman's dress shop sold cheaper dresses for $90 each and more expensive dresses for $140 each. The

Tema [17]

Answer:

Number of cheaper dresses sold is 35

Number of expensive dresses sold is 15

Step-by-step explanation:

Given:

Cost of cheaper dresses = $90

Cost of expensive dresses = $140

Total cost of the dresses = $5250

To Find:

Number of cheaper dress = ?

Number of expensive dress = ?

Solution:

Let

The number of cheaper dresses be x

The number of expensive dresses be y

(Number of cheaper dresses X cost of cheap dress) + (Number of Expensive dresses X cost of expensive dress) = $5250

$x \times90 +y \times 140 = 5250$ = $5250

It is given that the 20 more of the cheaper dresses than the expensive dresses is sold

So,

number of cheaper dress = 20 + number of expensive dress

x = 20 + y---------------------------------------(1)

$(20+y) \times90 +y \times 140 = 5250 = 5250$

$(20 \times 90 +y\times 90) +y \times 140= 5250$

$1800 + 90y+ 140y = 5250$

$1800 + 230y = 5250$

$230y =5250 -1800$

$230y = 3450$

$y = \frac{3450}{230}$

y = 15

Substituting y in (1)

x = 20 +15

x= 35

5 0

3 years ago

A certain composite number has 4 factors and the sum of them is 96. Find the number(hint the number is divisible by 7). Just don

ankoles [38]

Answer:

$\huge\boxed{77}$

Step-by-step explanation:

The number can be divisible by 7.

The multiples of 7 are 7,14,21,28,35,42,49,56,63,70,77,84 and so on

Finding the factors for all of the multiples of 7:

7 => 1,7 [Not 4 factors]

14 => 1,2,7,14 [4 factors but Sum = 24]

21 => 1,3,7,21 [4 factors but Sum = 32]

28 => 1, 2, 4, 7, 14, 28 [Not 4]

35 => 1,5,7,35 [4 factors but Sum = 48]

42 => 1, 2, 3, 6, 7, 14, 21, 42 [Not 4]

49 => 1,7,49 [Not 4]

56 => 1, 2, 4, 7, 8, 14, 28, 56 [Not 4]

63 => 1, 3, 7, 9, 21, 63 [Not 4]

70 => 1, 2, 5, 7, 10, 14, 35, 70 [Not 4]

77 => 1, 7, 11, 77 [4 factors and Sum = 96]

7 0

3 years ago

Read 2 more answers

Suppose that five ones and four zeros are arranged around a circle. Between any two equal bits you insert a 0 and between any tw

PolarNik [594]

Answer:

Using backward reasoning we want to show that "We can never get nine 0's".

Step-by-step explanation:

Basically in order to create nine 0's, the previous step had to have all 0's or all 1's. There is no other way possible, because between any two equal bits you insert a 0.

If we consider two cases for the second-to-last step:

There were 9 0's:

We obtain nine 0's if all bits in the previous step were the same, thus all bit were 0's or all bits were 1's. If the previous step contained all 0's, then we have the same case as the current iteration step. Since initially the circle did not contain only 0's, the circle had to contain something else than only 0's at some point and thus there exists a point where the circle contained only 1's.

There were 9 1's:

A circle contains only 1's, if every pair of the consecutive nine digits is different. However this is impossible, because there are five 1's and four 0's (we have an odd number of bits!), thus if the 1's and 0's alternate, then we obtain that 1's that will be next to each other (which would result in a 1 in the next step). Thus, we obtained a contradiction and thus assumption that the circle contains nine 0's after iteratins the procedure is false. This then means that you can never get nine 0's.

To summarize, in order to create nine 0's, the previous step had to have all 0's or al 1's. As we didn't start the arrange with all 0's, the only way is having all 1's, but having all 1's will not be possible in our case since we have an odd number of bits.

5 0

3 years ago

Denise has 7/8 pound of hamburger meat. How many 1/4 pound hamburgers can she make?

igor_vitrenko [27]

Answer:

3

Step-by-step explanation:

1/4 = 2/8

With 7/8 pounds of meat, you can make 3 patties (6/8) and have 1/8 pound leftover

8 0

3 years ago

Read 2 more answers

What is the total amount of liquid that the pyramid can hold

Feliz [49]

I think it’s about 300 cubic feet of liquid

7 0

3 years ago