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Vedmedyk [2.9K]

2 years ago

14

Which of the following statements holds true about the number group on the home tab. a) The number group contains options for ch

anging the appearance of the text.
b)The number group contains option for changing the Orientation and indentation of text.
c)The number group provides various format for specifying how do you want that values in a Cell to be displayed.
d)The number group provides options for applying border around the selected range of data.

1 answer:

nekit [7.7K]2 years ago

5 0

Answer:

i don't know what you're question is about

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In a survey, 30% of those questioned chose autumn as their favorite season. If 27 people chose autumn, then how many people were

makkiz [27]

90 people!

27/90=0.3

0.3x100= 30%

Hope that helped! :)

3 0

3 years ago

Read 2 more answers

Which line shows theINITIAL error in volume work?

aliina [53]

In step 2, V = $\frac{4}{3}(3.14)(37.5)$ show the error in volume work.

Solution:

Given data:

The steps shows it is sphere.

Radius of the sphere = 12.5

The value of π = 3.14

Volume of the sphere = $\frac{4}{3} \pi r^3$

Step 1:

$$V=\frac{4}{3} (3.14)(12.5)^3$

$$V=\frac{4}{3} (3.14)(12.5)(12.5)(12.5)$

Step 2:

$$V=\frac{4}{3} (3.14)(1953.125)$

Step 3:

$$V=\frac{4}{3} (6132.81)$

Step 4:

V = 8177.08 cubic units

This is the correct solution.

But in the given options, in step 2, 12.5 is multiplied by 3.

That is not the correct step. You have to do 12.5 × 12.5 × 12.5.

Hence in step 2, V = $\frac{4}{3}(3.14)(37.5)$ show the error in volume work.

7 0

3 years ago

Third-degree, with zeros of −3 , − 2 , and 1 , and passes through the point ( 3 , 11 ) .

Masja [62]

Answer:

y = ( x + 3 ) * ( x + 2 ) * ( x - 1 )* 11/60

Step-by-step explanation:

Lets y = f(x) in a cartesian coordinates

Having three zeros:

x = -3 ⇒ x = -2 ⇒ and x = 1

That meas that if x takes the above mentioned values " y " must be zero

therefore y must be of the form

f (x) = y = ( x + 3 ) * ( x + 2 ) * ( x - 1 ) (1)

In that case for y to be zero one of the factors should be zero or

y = 0 x + 3 = 0 and x = - 3 is a zero of the function y .

The same reasoning applies for the other two roots

Now we have to evaluate the other condition.

According to problem statement the function passes through the point ( 3, 11 ) , that means that when x = 3 , y have to be 11, therefore we plug in equation (1) that value to see what happens

y = ( x + 3 ) * ( x + 2 ) * ( x - 1 )

11 = ( 3 + 3 ) * ( 3 + 2 ) + ( 3 - 1) = 6*5*2 = 60

Then we adjust the expression (1) to meet the condition of the function passing through point ( 3 , 11) as:

y = ( 3 + 3 ) * ( 3 + 2 ) + ( 3 - 1) * 11/60 (2)

and check to see if we did right

for y to be zero x can be x = - 3 x = -2 and x = 1 in all these cases y = 0. And if x = 3 in equation (2) y = 11. And that what we want to shown. Then the solution is:

y = ( x + 3 ) * ( x + 2 ) * ( x - 1 )* 11/60

8 0

3 years ago

Is education related to programming preference when watching TV? From a poll of 80 television viewers, the following data have b

Luda [366]

Answer:

a) H0: There is no association between level of education and TV station preference (Independence)

H1: There is association between level of education and TV station preference (No independence)

b) $\chi^2 = \frac{(15-10)^2}{10}+\frac{(15-20)^2}{20}+\frac{(10-10)^2}{10}+\frac{(5-10)^2}{10}+\frac{(25-10)^2}{10}+\frac{(10-20)^2}{20} =33.75$

c) $\chi^2_{crit}=5.991$

d) Since the p value is lower than the significance level we enough evidence to reject the null hypothesis at 5% of significance, and we can conclude that we have dependence between the two variables analyzed.

Step-by-step explanation:

A chi-square goodness of fit test "determines if a sample data matches a population".

A chi-square test for independence "compares two variables in a contingency table to see if they are related. In a more general sense, it tests to see whether distributions of categorical variables differ from each another".

Assume the following dataset:

High school Some College Bachelor or higher Total

Public Broadcasting 15 15 10 40

Commercial stations 5 25 10 40

Total 20 40 20 80

We need to conduct a chi square test in order to check the following hypothesis:

Part a

H0: There is no association between level of education and TV station preference (Independence)

H1: There is association between level of education and TV station preference (No independence)

The level os significance assumed for this case is $\alpha=0.05$

The statistic to check the hypothesis is given by:

$\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}$

Part b

The table given represent the observed values, we just need to calculate the expected values with the following formula $E_i = \frac{total col * total row}{grand total}$

And the calculations are given by:

$E_{1} =\frac{20*40}{80}=10$

$E_{2} =\frac{40*40}{80}=20$

$E_{3} =\frac{20*40}{80}=10$

$E_{4} =\frac{20*40}{80}=10$

$E_{5} =\frac{40*40}{80}=20$

$E_{6} =\frac{20*40}{80}=10$

And the expected values are given by:

High school Some College Bachelor or higher Total

Public Broadcasting 10 20 10 40

Commercial stations 10 10 20 40

Total 20 30 30 80

Part b

And now we can calculate the statistic:

$\chi^2 = \frac{(15-10)^2}{10}+\frac{(15-20)^2}{20}+\frac{(10-10)^2}{10}+\frac{(5-10)^2}{10}+\frac{(25-10)^2}{10}+\frac{(10-20)^2}{20} =33.75$

Now we can calculate the degrees of freedom for the statistic given by:

$df=(rows-1)(cols-1)=(2-1)(3-1)=2$

Part c

In order to find the critical value we need to look on the right tail of the chi square distribution with 2 degrees of freedom a value that accumulates 0.05 of the area. And this value is $\chi^2_{crit}=5.991$

Part d

And we can calculate the p value given by:

$p_v = P(\chi^2_{3} >33.75)=2.23x10^{-7}$

And we can find the p value using the following excel code:

"=1-CHISQ.DIST(33.75,2,TRUE)"

Since the p value is lower than the significance level we enough evidence to reject the null hypothesis at 5% of significance, and we can conclude that we have dependence between the two variables analyzed.

7 0

4 years ago

What is the soulution of x^2 + 64 = 0

lys-0071 [83]

Solve out
x^2 + 64 = 0
x^2 = -64 ( we are going to use imaginary numbers to solve)
x = $i \sqrt{64}$
x = 8i, -8i final answers

3 0

3 years ago

Read 2 more answers