Question

Given two equations, MN = 20 and S=2-M+N Find the positive values of M and N . when S is minimum.​

Answer 1

The positive values of M and N are; 3.6 and 5.6 respectively.

Simultaneous equations

When S is minimum, s can be equated to 0.

On this note, it follows that the resulting equations are;

• MN = 20
• 0=2-M+N

From Substitution of M = 2 +N in the second equation; it follows that;

• (2+N)N = 20

• N² + 2N -20 = 0.

Hence, upon solving the quadratic equation;

• N = 5.6 or N = -3.6

Therefore, the positive value of N is; 5.6 and hence,

• M = 20/N = 20/5.6 = 3.6

Read more on simultaneous equations;

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Answer 2

The positive values of M and N are; 3.6 and 5.6 respectively.

Simultaneous equations

When S is minimum, s can be equated to 0.

On this note, it follows that the resulting equations are;

• MN = 20
• 0=2-M+N

From Substitution of M = 2 +N in the second equation; it follows that;

• (2+N)N = 20

• N² + 2N -20 = 0.

Hence, upon solving the quadratic equation;

• N = 5.6 or N = -3.6

Therefore, the positive value of N is; 5.6 and hence,

• M = 20/N = 20/5.6 = 3.6

Read more on simultaneous equations;

brainly.com/question/16863577