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3 years ago

Given two equations, MN = 20 and S=2-M+N Find the positive values of M and N . when S is minimum.

Mathematics

2 answers:

Dima020 [189]3 years ago

8 0

The positive values of M and N are; 3.6 and 5.6 respectively.

<h3>Simultaneous equations</h3>

When S is minimum, s can be equated to 0.

On this note, it follows that the resulting equations are;

MN = 20
0=2-M+N

From Substitution of M = 2 +N in the second equation; it follows that;

(2+N)N = 20

N² + 2N -20 = 0.

Hence, upon solving the quadratic equation;

N = 5.6 or N = -3.6

Therefore, the positive value of N is; 5.6 and hence,

M = 20/N = 20/5.6 = 3.6

Read more on simultaneous equations;

brainly.com/question/16863577

Doss [256]3 years ago

5 0

The positive values of M and N are; 3.6 and 5.6 respectively.

<h3>Simultaneous equations</h3>

When S is minimum, s can be equated to 0.

On this note, it follows that the resulting equations are;

MN = 20
0=2-M+N

From Substitution of M = 2 +N in the second equation; it follows that;

(2+N)N = 20

N² + 2N -20 = 0.

Hence, upon solving the quadratic equation;

N = 5.6 or N = -3.6

Therefore, the positive value of N is; 5.6 and hence,

M = 20/N = 20/5.6 = 3.6

Read more on simultaneous equations;

brainly.com/question/16863577

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2 years ago

Given two equations, MN = 20 and S=2-M+N Find the positive values of M and N . when S is minimum.​

Given two equations, MN = 20 and S=2-M+N Find the positive values of M and N . when S is minimum.