1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
son4ous [18]
2 years ago
14

Please i need help .........

Mathematics
2 answers:
Lena [83]2 years ago
7 0

g - (h + 14) / 3 = 20 - (4 + 14) / 3 = 20 - 18 / 3 = 20 - 6 = 14

The order I did the calculation is based on the Order of Operation, looked at my uploaded image to understand it

Hope that helps!

slava [35]2 years ago
4 0

Answer:

14

Step-by-step explanation:

20-(4+14)/3

20-(18)/3

20-6

14

Hope this helped.

A Brainliest is always appreciated.

You might be interested in
A Geiger counter counts the number of alpha particles from radioactive material. Over a long period of time, an average of 14 pa
UkoKoshka [18]

Answer:

0.2081 = 20.81% probability that at least one particle arrives in a particular one second period.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given interval.

Over a long period of time, an average of 14 particles per minute occurs. Assume the arrival of particles at the counter follows a Poisson distribution. Find the probability that at least one particle arrives in a particular one second period.

Each minute has 60 seconds, so \mu = \frac{14}{60} = 0.2333

Either no particle arrives, or at least one does. The sum of the probabilities of these events is decimal 1. So

P(X = 0) + P(X \geq 1) = 1

We want P(X \geq 1). So

P(X \geq 1) = 1 - P(X = 0)

In which

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-0.2333}*(0.2333)^{0}}{(0)!} = 0.7919

P(X \geq 1) = 1 - P(X = 0) = 1 - 0.7919 = 0.2081

0.2081 = 20.81% probability that at least one particle arrives in a particular one second period.

8 0
3 years ago
I need help finding m
Romashka-Z-Leto [24]

Answer:

i need this too hahahaha

8 0
2 years ago
What is the greatest common factor of 6a²b3 + 15ab^5– 9a^3b^2??
Roman55 [17]

Answer:

3ab^2

Step-by-step explanation:

Factor 6a^2b^3

= 2 * 3 * a * a * b * b * b

Factor 15ab^5

= 3 * 5 * a * b * b * b * b * b

Factor 9a^3b^2

3 * 3 * a * a * a * b * b

Common Factor

= 3 * a * b * b

Simplify

= 3ab^2

5 0
2 years ago
Explain your answer, please
Molodets [167]

.1.Scale Factor of Triangle STU to Triangle PQR= 1.5

2.Scale Factor of Trapezoid EFGH to Trapezoid JKLM =2

3. about 90 armadillo

1.Side ST: 15 ÷ Side PQ: 10 = 1.5

2.Side JM: 14 ÷Side EH: 7 = 2

3.843/7=120.428571429

843/4=210.75

210.75-120.428571429=90.321428571

This rounds to 90 armadillo

Hope this helps :3 ❤

8 0
3 years ago
Read 2 more answers
-1&lt;9+n&lt;17<br><br><br>i don't understand how to solve it
Ugo [173]

-1<9+n<17

-1-9<n<17-9

-10<n<8


6 0
3 years ago
Other questions:
  • 15/16 × 5/6<br><br> Reduce your answers to simplest form
    6·1 answer
  • A slump test is taken during the mid of the discharge of a concrete mix. The distance from the tempering rod (laying flat on top
    5·1 answer
  • A lead ball weighs 326 grams. Find the radius of the ball to the nearest tenth of a<br> centimeter.
    11·1 answer
  • Kenneth is 14 years younger than twice Sabrina’s age. Kenneth is 30 years old. How old is Sabrina?
    10·1 answer
  • I NEED HELP QUICKLY... The Student Council is selling raffle tickets to raise money for the Winter Dance. They have a total of 2
    15·2 answers
  • What is the length of BD?
    13·1 answer
  • &gt;<br> How many 3 card hands are possible with a 48-card deck?<br> The number of 3 card hands is a
    14·1 answer
  • A tree grows at the rate of 1½ inches every week. At this rate, how many weeks will it take the tree to grow 20.25 inches?
    5·1 answer
  • In 2016, a maglev train in Japan traveled 1.1 miles in 1045 seconds.
    8·1 answer
  • 50 points
    6·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!