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yarga [219]
3 years ago
14

8.2.38 Find the value of x. * * (Round to the nearest tenth as needed.)

Mathematics
1 answer:
Basile [38]3 years ago
6 0

Answer:

Step-by-step explanation:

To the nearest tenth 8.238

=8.2 to the nearest tenth

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Goryan [66]

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b

Step-by-step explanation:

the anwser to this question is b i think

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The value of a house has increased by 5% the house is now valued at £609000 what is the value of the house before the increase?
lutik1710 [3]

Answer:

Current \ price = 609000\\\\Let \ the \ original \ price \ be = x\\\\\% increase = 5 \% \ of \ x = \frac{5}{100} \times x = \frac{5x}{100}\\\\Price \ after \ increase, current\ price = \frac{5x}{100} + x\\\\

=> 609000 = \frac{5x}{100} + x\\\\=>609000 = \frac{105x}{100}\\\\=> x = \frac{609000 \times 100}{105}\\\\x = 580000

Therefore original price = $580,000

3 0
3 years ago
How to find the surface area of a this cuboid
aleksandrvk [35]

Answer:

<u><em>40</em></u>

Step-by-step explanation:

There are 6 sides. Four sides have 8 squares, 4 * 2, and the other 2 sides have 4, 2 * 2. 8 * 4 = 32, 4 * 2 = 8, 32 + 8 = 40

5 0
3 years ago
Which of these four sets of side lengths will form a right triangle? Set 1 4 cm, 5 cm, 6 cm Set 2 8 in., 12 in., 20 in. Set 3 10
Alenkasestr [34]

Answer:  The correct option is (D) SET 4.

Step-by-step explanation:  We are to select the correct set of side lengths that will form a right-angled triangle.

To form a right-angled triangle, we must have the following relation:

<em>Perpendicular² + Base² = Hypotenuse².</em>

<em>Hypotenuse is the length of the largest side; perpendicular and base are the two legs of the triangle.</em>

SET 1 :  14 cm, 5 cm, 6 cm.  

We have

5^2+6^2=25+36=61,\\\\14^2=196.

Therefore,

<em>Perpendicular² + Base² ≠ Hypotenuse².</em>

So, this set will not form a right-angled triangle.

SET 2 :  8 in., 12 in., 20 in.  

We have

8^2+12^2=64+144=208,\\\\20^2=400.

Therefore,

<em>Perpendicular² + Base² ≠ Hypotenuse².</em>

So, this set will not form a right-angled triangle.

SET 3 :  10 mm, 20 mm, 30 mm.  

We have

10^2+20^2=100+400=500,\\\\30^2=900.

Therefore,

<em>Perpendicular² + Base² ≠ Hypotenuse².</em>

So, this set will not form a right-angled triangle.

SET 4 :  12 ft, 16 ft, 20 ft.  

We have

12^2+16^2=144+256=400,\\\\20^2=400.

Therefore,

<em>Perpendicular² + Base² = Hypotenuse².</em>

So, this set will form a right-angled triangle.

Thus, the SET 4 will form a right-angles triangle.

Option (D) is correct.

5 0
3 years ago
Read 2 more answers
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