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3 years ago

8.2.38 Find the value of x. * * (Round to the nearest tenth as needed.)

Mathematics

1 answer:

Basile [38]3 years ago

6 0

Answer:

Step-by-step explanation:

To the nearest tenth 8.238

=8.2 to the nearest tenth

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The equation which correctly represents this situation is

uranmaximum [27]

Answer:

C) x2 + x = 306

Step-by-step explanation:

x2 + x = 306

x2 + x - 306 = 0

x2 + 18x - 17x + 18 * (-17) = 0

x ( x + 18) - 17 (x +18) =0

(x + 18) (x - 17 ) = 0

x = -18 or 17

5 0

3 years ago

William and his puppy Rover are out for a morning jog at a comfortable pace of 10 minutes per mile. If they keep up this pace fo

mojhsa [17]

Answer:

12 miles

Step-by-step explanation:

60 min in 1 hr and 10 min = 1 mile..... so 6, 10 min intervals..... and so 6 time 2 is 12

8 0

2 years ago

Find the first three terms of the sequence below n² – n + 4

sergejj [24]

Answer:

First three terms of given sequence are

9, 13, 17

Step-by-step explanation:

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2 years ago

Find the distance between the points (1, 5) and (1, -4).

Ganezh [65]

Answer:

Step-by-step explanation:

$\tt distance=\sqrt{(1-1)^2+(-4-5)^2}=\sqrt{0^2+9^{2}}=\sqrt{9^2} =9$

6 0

3 years ago

Read 2 more answers

What is the product?

fredd [130]

Answer:

$\frac{4k + 2}{k^{2}-4 }$ × $\frac{k-2}{2k+1}$ = $\frac{2}{k + 2}$

Step-by-step explanation:

$\frac{4k + 2}{k^{2}-4 }$ × $\frac{k-2}{2k+1}$

To solve the above, we need to follow the steps below;

4k+2 can be factorize, so that;

4k +2 = 2 (2k + 1)

k² - 4 can also be be expanded, so that;

k² - 4 = (k-2)(k+2)

Lets replace 4k +2 by 2 (2k + 1)

and

k² - 4 by (k-2)(k+2) in the expression given

$\frac{4k + 2}{k^{2}-4 }$ × $\frac{k-2}{2k+1}$

$\frac{2(2k+ 1)}{(k-2)(k+2)}$ × $\frac{k-2}{2k+1}$

(2k+1) at the numerator will cancel-out (2k+1) at the denominator, also (k-2) at the numerator will cancel-out (k-2) at the denominator,

So our expression becomes;

$\frac{2}{k + 2}$

Therefore, $\frac{4k + 2}{k^{2}-4 }$ × $\frac{k-2}{2k+1}$ = $\frac{2}{k + 2}$

3 0

3 years ago

Read 2 more answers