Answer:
The answer to your question is 242 ml
Explanation:
Data
HI 0.211 M Volume = x
KMnO₄ 0.354 M Volume = 24 ml
Balanced Chemical reaction
12HI + 2KMnO₄ + 2H₂SO₄ → 6I₂ + Mn₂SO₄ + K₂SO₄ + 8H₂O
Process
1.- Calculate the moles of KMnO₄ 0.354 M in 24 ml
Molarity = moles / volume (L)
moles = Molarity x volume (L)
moles = 0.354 x 0.024
moles = 0.0085
2.- From the balanced chemical reaction we know that HI and KMnO₄ react in the proportion 12 to 2. Then,
12 moles of HI --------------- 2 moles of KMnO₄
x --------------- 0.0085 moles of KMnO₄
x = (0.0085 x 12)/2
x = 0.051 moles of HI
3.- Calculate the milliliters of HI 0.211 M
Molarity = moles/volume
Volume = moles/molarity
Volume = 0.051/0.211
Volume = 0.242 L or Volume = 242 ml
<h2>ingredients
:</h2>
2 ¾ cups all-purpose flour
1 teaspoon baking soda
½ teaspoon baking powder
1 cup butter, softened
1 ½ cups white sugar
1 egg
1 teaspoon vanilla extract
Explanation:
Step 1
Preheat oven to 375 degrees F (190 degrees C). In a small bowl, stir together flour, baking soda, and baking powder. Set aside.
Step 2
In a large bowl, cream together the butter and sugar until smooth. Beat in egg and vanilla. Gradually blend in the dry ingredients. Roll rounded teaspoonfuls of dough into balls, and place onto ungreased cookie sheets.
Step 3
Bake 8 to 10 minutes in the preheated oven, or until golden. Let stand on cookie sheet two minutes before removing to cool on wire racks.
Partner Tip
Reynolds® Aluminum foil can be used to keep food moist, cook it evenly, and make clean-up easier.
creds to : https://www.allrecipes.com/recipe/9870/easy-sugar-cookies/
hope you have a wonderful day :)
Answer: The concentration of Silver Nitrate in solution # 4 is 3.5x10-6 M
Explanation:
When calculating the concentration of a dilute solution, we use the equation:
C1V1 = C2V2
Where C1 = concentration of the known solution
V1= amount of know solution
C2= new concentration
V2= capacity of the flask
Keep in mind that solution #2 is not related to the preparation of solutions #3 y #4, so the concentration of #2 is irrelevant.
For calculating the concentration of solution #4 , we first calculate the concentration of the solution #3, that comes from the solution #1.
- Calculating concentration solution #3
- C1V1 = C3V3
- C3= (0.0002442 M * 10mL) / 250mL
- C3= 9.8X10-6M
2. Calculating concentration solution #4
- C3V3 = C4V4
- C4= (9.8X10-6M *18mL) / 50mL
- C4= 3.5X10-6 M
The balanced reaction that describes the reaction between hydrogen and oxygen to produce water is expressed 2H2 + O2 = 2H2O. Hence for each mole of oxygen used, two moles of hydrogen is used and two moles also of water is produced.