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Lady bird [3.3K]
3 years ago
8

What type of reactive intermediate is formed in the reaction of an alkene with aqueous acid to give an alcohol?

Chemistry
1 answer:
Mariana [72]3 years ago
5 0

Answer:

The intermediate is carbocation.

Explanation:

The reaction of alkene with an acid to give alcohol is an electrophilic addition reaction.

In electrophilic reaction, the alkene is being attacked by an alkene.

in case of aqueous acid reaction with alkene , the electrophile is [H⁺].

When the proton attacks the alkene it generates carbocation.

The carbocation generated is formed based on stability of carbocation.

The mechanism is shown in the figure.

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The percent by mass of bicarbonate (HCO3−) in a certain Alka-Seltzer product is 32.5 percent. Calculate the volume of CO2 genera
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Answer:

The volume of carbon dioxide gas generated 468 mL.

Explanation:

The percent by mass of bicarbonate in a certain Alka-Seltzer = 32.5%

Mass of tablet = 3.45 g

Mass of bicarbonate =3.45 g\times \frac{32.5}{100}=1.121 mol

Moles of bicarbonate ion = \frac{1.121 g/mol}{61 g/mol}=0.01840 mol

HCO_3^{-}(aq)+HCl(aq)\rightarrow H_2O(l)+CO_2(g)+Cl^-(aq)

According to reaction, 1 mole of bicarbonate ion gives with 1 mole of carbon dioxide gas , then 0.01840 mole of bicarbonate ion will give:

\frac{1}{1}\times 0.01840 mol=0.01840 mol of carbon dioxide gas

Moles of carbon dioxide gas  n = 0.01840 mol

Pressure of the carbon dioxide gas = P = 1.00 atm

Temperature of the carbon dioxide gas = T = 37°C = 37+273 K=310 K

Volume of the carbon dioxide gas = V

PV=nRT (ideal gas equation)

V=\frac{nRT}{P}=\frac{0.01840 mol\times 0.0821 atm L/mol K\times 310 K}{1.00 atm}=0.468 L

1 L = 1000 mL

0.468 L =0.468 × 1000 mL = 468 mL

The volume of carbon dioxide gas generated 468 mL.

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What charge is there on a lithium ion?
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This family (ethane, propane, butane, etc) of materials is likely to have following set of properties.

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