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2 years ago

Answer please I can’t figure it out

Mathematics

1 answer:

Natali [406]2 years ago

6 0

C because it is 2(3/2w +w)=5w

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Given point A (3, 8) and point B (-5, 1). Find the following: a.) The coordinates of the midpoint of segment AB. Write your answ

ss7ja [257]

Answer:

Mid point:

$= ( \frac{3 + - 5}{2} , \: \frac{1 + 8}{2} ) \\ = ( - 1, \: 4.5)$

distance:

$= \sqrt{ {( - 5 - 3)}^{2} + {(1 - 8)}^{2} } \\ = \sqrt{64 + 49} \\ = \sqrt{113} \\ = 10.6 \: units$

slope:

$= \frac{1 - 8}{ - 5 - 3} \\ = \frac{ - 7}{ - 8} \\ = \frac{7}{8}$

8 0

2 years ago

Find the measure of the angle, round to the nearest tenth: Sin X = .7547

dimulka [17.4K]

SIN(x) = .7547
X = INVERSE-SIN(.7547)
X = 49.0 degrees

4 0

2 years ago

What is the area of the triangle in the coordinate plane?

AnnZ [28]

The answer to this is C.54 units² .

Area=1/2 base*height
base=12
height=9
12*9=108
108/2=54
Area=54

5 0

3 years ago

Read 2 more answers

A jumper in the long-jump goes into the jump with a speed of 12 m/s at an angle of 20° above the horizontal. How far does the ju

weeeeeb [17]

Answer:

x = 9.5 m

Step-by-step explanation:

Given:

This problem is based on 2D motion kinematics equations:

$V_0 = 12 m/s$

$\theta = 20^0$

$g=9.8 m/s^2$

At maximum height:

$V_y = 0$

Components of initial velocity:

$V_0x = V_0 cos (\theta) =(12 )(cos (20^0)) = 11.3 m/s$

$V_0x = V_0 sin (\theta) = (12)(sin (20^0)) = 4.10 m/s$

To find time to reach maximum height:

$V_y = V_0y -gt$

Plugging in the known values:

0 = 4.10 - 9.8t

$t = \frac{-4.10}{-9.8}$

$t = 0.418 s$

Total time = 2t = 2(0.418) = 0.836 s

to find horizontal distance covered:

$x = (V_0x)(t)\\x = (11.3)(0.836)\\x = 9.5 m$

8 0

3 years ago

PLS HELP. I will give brainliest if you are correct!!!

pshichka [43]

We can see here that there are 2 triangular bases on the prism.

To calculate the area of a triangle, we multiply the base and the height and then divide by 2.

A = 8 x 6 /2

A = 48/2

A = 24

Hope it helps!

7 0

1 year ago