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Ludmilka [50]
2 years ago
6

What is the slope of a line perpendicular to the line whose equation is 15x−18y=−486. Fully simplify your answer.

Mathematics
1 answer:
bazaltina [42]2 years ago
4 0
The answer is -6/5

First convert the equation to y=mx+b form
you’ll get y=5/6x+27
then to find the line perpendicular to this equation, you have the flip the slope.
ending with -6/5
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Find the inverse of f(x)=(x−5)/(−4x−2)
uysha [10]

Answer:

{f}^{ - 1} (x)= \frac{  5 - 2x }{ 4x  + 1}

Step-by-step explanation:

The given rational function is

f(x) =  \frac{x - 5}{ - 4x - 2}

Let

y =  \frac{x - 5}{ - 4x - 2}

Interchange x and y

x=  \frac{y- 5}{ - 4y - 2}

Cross multiply

x( - 4y - 2)= y- 5

Expand

- 4xy   - 2x= y- 5  \\ - 4xy  - y=  2x - 5 \\y( - 4x - 1)=  2x - 5

Solve for y;

y= \frac{  2x - 5}{ - 4x - 1}

or

y= \frac{  5 - 2x }{ 4x  + 1}

Therefore

{f}^{ - 1} (x)= \frac{  5 - 2x }{ 4x  + 1}

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3 years ago
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12345 [234]

Answer:

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Step-by-step explanation:

8 0
3 years ago
A phone manufacturer wants to compete in the touch screen phone market. He understands that the lead product has a battery life
alisha [4.7K]

Answer:

a)

The null hypothesis is H_0: \mu \leq 10

The alternative hypothesis is H_1: \mu > 10

b-1) The value of the test statistic is t = 1.86.

b-2) The p-value is of 0.0348.

Step-by-step explanation:

Question a:

Test if the battery life is more than twice of 5 hours:

Twice of 5 hours = 5*2 = 10 hours.

At the null hypothesis, we test if the battery life is of 10 hours or less, than is:

H_0: \mu \leq 10

At the alternative hypothesis, we test if the battery life is of more than 10 hours, that is:

H_1: \mu > 10

b-1. Calculate the value of the test statistic.

The test statistic is:

We have the standard deviation for the sample, so the t-distribution is used to solve this question

t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, s is the standard deviation and n is the size of the sample.

10 is tested at the null hypothesis:

This means that \mu = 10

In order to test the claim, a researcher samples 45 units of the new phone and finds that the sample battery life averages 10.5 hours with a sample standard deviation of 1.8 hours.

This means that n = 45, X = 10.5, s = 1.8

Then

t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}

t = \frac{10.5 - 10}{\frac{1.8}{\sqrt{45}}}

t = 1.86

The value of the test statistic is t = 1.86.

b-2. Find the p-value.

Testing if the mean is more than a value, so a right-tailed test.

Sample of 45, so 45 - 1 = 44 degrees of freedom.

Test statistic t = 1.86.

Using a t-distribution calculator, the p-value is of 0.0348.

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Cuocitis vivvbivi it such in
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Step-by-step explanation

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