We know, s = n/2 [a + l ]
Here, n = 1010
a = 1
l = 1010
Substitute their values,
s = 1010/2 [1 + 1010]
s = 505 [ 1011]
s = 510555
In short, Your Answer would be 5,10,555
Hope this helps!
Answer:
f(-2) = 4
f(0.5)= 0
f(1)=1
Step-by-step explanation:
The sum of those is 800,201
Let us compute first the probability of ending up an odd number when rolling a dice. A dice has faces with numbers 1 up to 6. The odd numbers within that is 3 (1, 3 and 5). Therefore, each dice has a probability of 3/6 or 1/2. Then, you use the repeated trials formula:
Probability = n!/r!(n-r)! * p^r * q^(n-r), where n is the number of tries (n=6), r is the number tries where you get an even number (r=0), p is the probability of having an even face and q is the probability of having an odd face.
Probability = 6!/0!(6!) * (1/2)^0 * (1/2)^6
Probability = 1/64
Therefore, the probability is 1/64 or 1.56%.
Answer:
minimum
Step-by-step explanation:
