The Vanderbilt University Institute for Imaging Science (VUIIS) Center for Computational Imaging (CCI) is known to have made a database built on XNAT housing that is said to house about a quarter of a million scans.
<h3>What is the institute about?</h3>
The above study was said go have used the database that gave a framework for:
- Fast prototyping
- large volume batch processing of images
- Scalable project management.
The above system is one that make use of the web-based interfaces of XNAT and REDCap to give room for graphical interaction.
Hence, the Distributed Automation for XNAT (DAX) package, is one that shares computation in all of Vanderbilt Advanced Computing Center for Research and Education high form of computing center.
Therefore, The Vanderbilt University Institute for Imaging Science (VUIIS) Center for Computational Imaging (CCI) is known to have made a database built on XNAT housing that is said to house about a quarter of a million scans.
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All of the aforementioned are implied by Viagra advertisements except that: women should be more se-xually assertive.
<h3>What is an advertisement?</h3>
An advertisement can be defined as consumer promotions programs that are designed and developed with the sole intention of making the various goods (products) or services which are being offered by a business firm to become known, popular and familiar to all of its customers and potential customers.
In this scenario, we can infer and logically that Viagra advertisements which depicts it as being an aphrodisiac and se-xual enhancer doesn't imply that women should be more se-xually assertive over their male counterparts (partners).
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Step-by-step explanation:
Assuming the data is as shown, restaurant X has a mean service time of 180.56, with a standard deviation of 62.6.
The standard error is SE = s/√n = 62.6/√50 = 8.85.
At 95% confidence, the critical value is z = 1.960.
Therefore, the confidence interval is:
180.56 ± 1.960 × 8.85
180.56 ± 17.35
(163, 198)
Restaurant Y has a mean service time of 152.96, with a standard deviation of 49.2.
The standard error is SE = s/√n = 49.2/√50 = 6.96.
At 95% confidence, the critical value is z = 1.960.
Therefore, the confidence interval is:
152.96 ± 1.960 × 6.96
152.96 ± 13.64
(139, 167)
