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disa [49]
2 years ago
6

Radius of Cirlce A is 7ft. The radius of Circle B is 2ft greater than the radius of Circle A. The radius of Circle C is 5ft grea

ter than the radius of circle B. The radius of circle D is 3ft less than the radius of Circle C. What is the area of each circle? How many times greater than the area of Circle A is the area of Circle D?
Mathematics
1 answer:
Flauer [41]2 years ago
4 0

Answer:

Given: Radius of circle (r)=

π

7

Area of the circle =π(r)

2

=π×(

π

7

)

2

=π×

π

49

=49cm

Step-by-step explanation:

please mark me as brainlist please

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Step-by-step explanation:

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3 years ago
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3 years ago
Read 2 more answers
(-10,2) (-5,-1) find mid point
zmey [24]

The Mid - point of the line segment is at coordinates -  M(- 7.5, 0.5)

We have two coordinate points -  A(- 10, 2)  and  B(- 5, -1)

We have to find the midpoint of this line AB.

<h3>What is Mid - Point Theorem?</h3>

It states that a line with endpoint coordinates as - (x_{1} ,y_{1} ) and (x_{2} ,y_{2} ) has its mid - point at the coordinates -

(x_{M} ,y_{M} ) =( \frac{x_{1} +x_{2} }{2} , \frac{(y_{1} +y_{2} )}{2} )

According to question, we have -

First coordinate Point -  (x_{1} ,y_{1} ) = (- 10, 2)

Second coordinate Point - (x_{2} ,y_{2} ) = (- 5, - 1)

Using the Mid - Point formula, we get -

(x_{M} ,y_{M} ) =( \frac{x_{1} +x_{2} }{2} , \frac{y_{1} +y_{2} }{2} ) =

x_{M} = \frac{-10-5}{2} = \frac{-15}{2} = - 7.5\\\\y_{M} = \frac{2 - 1}{2}  = \frac{1}{2} = 0.5

Hence, the Mid - point of the line segment is at coordinates -

M(- 7.5, 0.5)

To solve more questions on Mid - points, visit the link below -

brainly.com/question/25377004

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1 year ago
PLEASE HELP ME THESE ARE MY LAST POINTS PLEASEEE
Julli [10]
About 16 copies cost the same amounts
5 0
3 years ago
Read 2 more answers
How many solutions does the equation 6y - 3y -7 = -2 +3 have?
kenny6666 [7]

Answer:

6y - 3y - 7 = -2 +3

Simplify both sides:

3y -7 = 1

Add 7 to both sides:

3y = 8

Divide both sides by 3:

y = 8/3 = 2 2/3

There is only one solution.

8 0
3 years ago
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