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Let A be a 3×2 matrix, L its left inverse, and R its right inverse. L and R are then matrices such that LA = I₂ (the 2×2 identity matrix) and AR = I₃ (the 3×3 identity matrix). Clearly L must be 2×3 and R must be 3×2 in order for the matrix products to be defined.
To find L and R, we start by introducing a square matrix on the the left sides of either equation above. In particular, we uniformly multiply both sides by the transpose of A, then solve for the inverse.
For the left inverse, we have
We do the same thing for the right inverse, but take care with how we multiply both sides of AR = I₃.
Answer:
15 dozens of cakes
Step-by-step explanation:
It is given that Jeanna is making cupcakes for her family and she normally makes 2 dozens of red velvet cakes and 3 dozens of gingerbread spice cakes. But as everybody is staying at home, Jeanna wants to increase the standard amount by 3 for enough cakes.
So,
2 dozens of velvet cakes, i.e.
2 x 12 = 24 red velvet cakes
Increasing this amount by 3 times will give us 24 x 3 = 72 red velvet cakes.
Similarly,
3 dozens of gingerbread spice cakes, i.e.
3 x 12 = 36 gingerbread spice cakes
Increasing this amount by 3 times will give us 36 x 3 = 108 gingerbread spice cakes.
Therefore the total number of cakes is = 72 + 108
= 180 cakes.
We know 1 dozen = 12
Therefore dividing 180 cakes by 12, we get
= 15 dozen cakes.
Therefore, now Jeanna will have to make 15 dozens of cupcakes for all.
Answer:
B,
Step-by-step explanation:
This problem is essentially asking one to envision a line passing through the set of points on the coordinate plane, then to find the constant of proportionality of that line. The constant of proportionally, also known as the rate of change, or the slope, is a number that can be used to describe the range that happens between points on a line. The following formula can be used to find the slope of a line passing through a set of points.
Where the points () and (
) are points on the line.
As one can see, on the given coordinate plane, the points (), and (
) are on the coordinate plane. Substitute these points into the formula to find the slope of the line, then simplify to evaluate the equation and find the slope,
(), (
)