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shutvik [7]
3 years ago
6

Have three witches each holding a broom and a spoon. Witches say witch plus witch plus witch =45. Three brooms say broom plus br

oom plus a broom =21 and three spoons say spoon plus spoon plus spoon = 12 then final question is a plain witch plus broom x spoon equal a ? What’s answer?
Mathematics
2 answers:
GrogVix [38]3 years ago
6 0

Answer:

a=43

Step-by-step explanation:

w+w+w= 45 which means 15+15+15=45

b+b+b=21 which means 7+7+7=21

s+s+s=12 which means 4+4+4=12

w+b×s= a which means 15+7×4= 43

(hope this helps)

matrenka [14]3 years ago
3 0

Answer:

<em>The answer to the question is 43</em>

Step-by-step explanation:

<em>Let us recall the values from the following question stated:</em>

<em>Three witches each holds a broom and a spoon, saying plus witch plus witch = 45</em>

<em>Three brooms say broom plus broom plus a broom at = 21</em>

<em>Three spoons say spoon plus spoon plus = 21</em>

<em> Now, let us find when a plain witch plus broom x spoon </em>

<em>Then,</em>

<em>Three witches = 45, resulting to  15+15+15=45 </em>

<em> Three brooms (b+b+b) which is =21 or  7+7+7=21 </em>

<em>Three spoons (s+s+s) is =12  or 4+4+4=12 </em>

<em> we make use of multiplication for the witches, the brooms, and the spoons </em>

<em>Therefore</em>

<em>w+b×s= a,  which is 15+7×4= 43 </em>

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The probability that a student participates in both sports and drama is 0.14.

<h3>What is the formula for P(AUB), where A and B are any two events?</h3>

If A and B are any two events, then the probability of the joint event (A\cup B) is given by the following formula: P(A\cup B)=P(A)+P(B)-P(A\cap B)

Given that 42% of the students participate in sports and 25% of the students participate in drama and 53% of the students participate in either sports or drama.

Suppose S denotes that "a student participates in sports" and D denotes that "a student participates in drama".
So, we have P(S)=\frac{42}{100}=0.42, P(D)=\frac{25}{100}=0.25, P(S\cup D)=\frac{53}{100}=0.53.

We want to find the probability that a student participates in both sports and drama i.e., we want to find P(S\cap D).

By the above formula, we obtain:

P(S\cup D)=P(S)+P(D)-P(S\cap D)\\\Longrightarrow P(S\cap D)=P(S)+P(D)-P(S\cup D)\\\Longrightarrow P(S\cap D)=0.42+0.25-0.53\\\therefore P(S\cap D)=0.14=\frac{14}{100}

Therefore, the probability that a student participates in both sports and drama is 0.14.

To learn more about probability, refer: brainly.com/question/24756209

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From a population of 200,000,000 elements, the standard deviation is known to be 14. A sample of 49 elements is selected. It is
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Answer:

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Step-by-step explanation:

Given that:

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The formula for calculating the standard error can be expressed as:

S.E = \dfrac{\sigma}{\sqrt{n}}

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4 0
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Answer:

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7. -10y= 5x+20

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