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3 years ago

Find the area of each figure

Mathematics

1 answer:

Anon25 [30]3 years ago

7 0

Area of trapezoid = a + b/2 * h
a = 20, b = 9, h = 21/-16
20+9/2 * (21-16) = 29/2 * 5 = 72.5
The area of the trapezoid = 72.5 in^2

Area of the rectangle = l * w
l = 16, w = 20
16 * 20 = 320
The area of the rectangle: 320 in^2

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Hi student, let me help you out! :)

. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .

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$\triangle~\fbox{\bf{KEY:}}$

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So we need to find the absolute value of 98, which is:

$\star~\star\mathrm{98}~\star~\star$

$\ddot\bigstar$ Remember this...

$\fbox{The\;absolute\;value\;is\;a\;number's\;distance\;from\;zero}$

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olga2289 [7]

Answer:

View image

Step-by-step explanation:

You treat inequality questions just like normal equation with an equal sign. You only have to worry about the inequality when you do the shading part.

Your first goal is to solve for y, which I did at the top.

And remember that when you divide/multiply by a negative number you have to flip the inequality sign.

So the first equation is already in term of y. (y < 2x + 4)

So you only have to solve for y for -3x - 2y ≥ 6.

I solved that and got y ≤ -3/2x - 3.

Now you have 2 equations. y < 2x + 4 and y ≤ -3/2x - 3

First you gotta treat it like a normal equation and graph them.

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btw. < and > have dotted lines, while ≤ and ≥ have solid lines.

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