G es to prove that if a, b, and c are integers, where a ≠ 0 and c ≠ 0, such that ac | bc, then a |

1 answer:

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$ac\mid bc$ means there exists an integer $n$ such that $ac=bcn$ . We can divide both sides by $c$ because $c\neq0$ . This implies $a=bn$ for some integer, which is identically $a\mid b$ .

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9. Complete the reasons in the proof below.

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For a), this is clearly a given as it is literally to the right of where it says “Given:”
For b), since ON bisects ∠JOH, this means that it splits it into two separate angles - JON and HON, which are similar due to that bisects mean that it splits it equally into two halves
For c), since NO is the same thing as NO, it is equal to itself
For d), since AAS (angle-angle-side) congruence states that if there are two angles that are congruent (proved in a) and b) ) as well as that a side is congruent (proved in c) ), two triangles are congruent
For e), since two triangles are congruent, every side must have one side that it matches up to in the other triangle. As the opposite side of angle H is JO and the opposite side of angle J is OH, and ∠J=∠H, those two are congruent. As JN and HN are the two sides left, they must be congruent.

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2 years ago

Can someone help me with thiis?

3241004551 [841]

I believe the expression would be 7(g)+7

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