こんにちは、これを読んでいただきありがとうございます。私は英語が話せないので、あなたの質問には答えられないと言いたかっただけです。ごめんなさい。
Answer:
6cm^3
Step-by-step explanation:
V = l*w*h
........... ....
Answer:
The probability that a randomly selected monthly cell phone bill is less than $95 is 0.9772
Step-by-step explanation:
The average monthly household cellular phone bill is $73.

Local monthly household cell phone bills are normally distributed with a standard deviation of $11.

We are supposed to find the probability that a randomly selected monthly cell phone bill is less than $95 i.e.P(x<95)


Z=2
Refer the z table for p value
So,p value = 0.9772
Hence the probability that a randomly selected monthly cell phone bill is less than $95 is 0.9772
This is so hard not gonna lie :0