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Iteru [2.4K]
2 years ago
6

True or false/ the extension of all database files in access is exe ………….

Computers and Technology
1 answer:
Hitman42 [59]2 years ago
6 0
<h3><em>Answer:</em></h3>

True

<h3><em>Hope it helps.</em></h3>

You might be interested in
C++ coding, help
Zanzabum

Answer:

The program in C++ is as follows:

#include <fstream>

#include <iostream>

#include <iomanip>

using namespace std;

int main() {

 string filename;

 cout<<"Filename: ";

 cin>>filename;

 ifstream inFile(filename);

 if(!inFile) {

   cout << endl << "Cannot open file " << filename;

   return 1;  }  

 ofstream fout;

 ifstream fin;

 fin.open("invalid-numbers.txt");  

 fout.open ("invalid-numbers.txt",ios::app);  

 double sum = 0; int valid = 0; int invalid = 0;

 double num = 0;

 while(!inFile.eof()) {

   inFile >> num;

   if(num >= 0 && num<=110){   sum+=num; valid++; }

else{ invalid++;

if(fin.is_open()){

   fout<<fixed<<setprecision(2)<<num<<"\n";    }  }  }

 fin.close();

 fout.close();

 inFile.close();

 cout<<"Total values: "<<valid+invalid<<endl;

 cout<<"Invalid values: "<<invalid<<endl;

 cout<<"Valid values: "<<valid<<endl;

 cout<<"Average of valid values: "<<fixed<<setprecision(2)<<sum/valid<<endl;    

 double inv;

 ifstream inFiles("invalid-numbers.txt");

 while(!inFiles.eof()) {

   inFiles >> inv;

   cout<<inv<<"\n";

}

inFiles.close();

 return 0;

}

Explanation:

See attachment for source file where comments are used to explain each line

Download cpp
4 0
3 years ago
Word provides a quicker way through the
Greeley [361]
You didn't finish your question 

4 0
4 years ago
Before making a dish, we want to check whether we already have the necessary ingredients in our pantry or whether we need to go
Leona [35]

Answer:

class Pantry(AD):

              def __init__(self, ingredients):

""" We initialize the Pantry class by passing the ingredients that were passed in to the initializer for the superclass AD"""

              super().__init__(ingredients)

              def needed_ingredients(self, recipes):

""" Given a list of recipes, computes which ingredients to buy, and in which quantity to be able to make all recipes. Can be implemented in 10 lines of code."""

              # define the object new_pantry to contain the ingredients needed

               new_pantry = Pantry({})

                ingredients_present = self

                # loop over the recipes in the list

                for recipe in recipes:

                        # convert ingredients of recipe from AD to Pantry

                        ingredients = Pantry(recipe.ingredients)

                        # subtract the recipe's ingredients from ingredients_present

                          ingredients_present = ingredients_present - ingredients

                        # loop over the ingredients_present for key in ingredients_present:

                       # if any ingredients's quantity < 0, add it to new_pantry

                                                           if ingredients_present[key] < 0:

# check if ingredient is present in new_pantry, add the quantity to existing quantity

                                                               if key in new_pantry:

                                            new_pantry[key] += -1*(ingredients_present[key])

else: # if ingredient is not present in new_pantry, make a new entry for the ingredient

                                               new_pantry[key] = -1*(ingredients_present[key])

ingredients_present[key] = 0      # set the quantity of the ingredient in ingredients_present to 0

Explanation:

I believe everything else is provided in the question.

Copy all the details you were provided in the question as it is and add the needed_ingredients in the Pantry class.

If you are getting any assertion error, Update the code to set the negative quantities in ingredients_present to 0

6 0
3 years ago
Can someone please help me with drawing a state transition table for the attached state diagram?
ankoles [38]

Answer:

see below diagrams.

You could extend that by defining two outputs:

- Lock open/closed indicator

- Error indicator

Then all you have to do is design a circuit...

8 0
2 years ago
Create a game that rolls two dies (number from 1 to 6 on the side) sequentially for 10 times (use loop). If at least once out of
Alex73 [517]

Answer:

Explanation:

The following code is written in Java and loops through 10 times. Each time generating 2 random dice rolls. If the sum is 10 it breaks the loop and outputs a "You Win" statement. Otherwise, it outputs "You Lose"

import java.util.Random;

class Brainly {

   public static void main(String[] args) {

       UseRandom useRandom = new UseRandom();

       boolean youWin = false;

       for (int x = 0; x<10; x++) {

           int num1 = useRandom.getRandom(6);

           int num2 = useRandom.getRandom(6);

           if ((num1 + num2) == 10) {

               System.out.println("Number 1: " + num1);

               System.out.println("Number 2: " + num2);

               System.out.println("You Win");

               youWin = true;

               break;

           }

       }

       if (youWin == false) {

           System.out.println("You Lose");

       }

   }

}

class UseRandom{

   public int getRandom(int n)

   {

       Random r=new Random();

       int rand=r.nextInt(n);

       return rand;

   }}

8 0
3 years ago
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