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zzz [600]
2 years ago
11

A beacon is flashing on top of a 50 foot tower. A 6 foot tall man walks constantly away from the tower at 5 feet/sec. At the ins

tant the man is 30 feet away from the tower, what rate is the tip of his shadow moving away from the tower
Mathematics
1 answer:
Viefleur [7K]2 years ago
7 0

Answer:\frac{253}{44}

Step-by-step explanation:

ignore the "at the instant the man is 30 feet away" part, set it as X and the man's shadow as Y.

Similar triangles so we can do \frac{50}{x+y}  = \frac{6}{y}.

Solve for it we get 44y = 6x

Differentiate relative to time t, we get 44y' = 6x'.

change in x (x') is equal to 5. And we get the answer y' = \frac{33}{44}.

the \frac{33}{44} ft/sec is the rate of which the length of the shadow is changing. add 5 to it for the rate of the tip of his shadow moving away from the tower.

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Answer:

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8 0
3 years ago
Pls help me solve it!
vekshin1

Answer:

A= 40°

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Step-by-step explanation:

Since it says if the triangles were accurately drawn, then A would be the same  degree as Q. C would be the same degree as P. B would be the same degree as R. Since R's degree is missing I knew that a obtuse triangle was 90°. I added 40+15 and got 55. Then i subtracted 90-55 and got 35. So the unknown value would be 35°.

I hope this helps.

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