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Westkost [7]
3 years ago
6

Yesterday, a Bakery baked 54 loaves of bread in 20 minutes today the bakery needs to bake 375 loaves of bread at this rate predi

ct how long it would take to bake the bread
Mathematics
2 answers:
arsen [322]3 years ago
7 0
There are 54 can go into 375, 6 times. So if 54 can be done in 20 mins, you do 6 x 20 =120mins. Then you divide by 60 mins and you'll get 2 hours. so 2 hours is your answer.
alukav5142 [94]3 years ago
3 0
It would take about 2 hours and 20 mins but they would have 3 leftovr
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Evaluate the expression below at x = 5. x/35 + 5x^2
kramer

Answer:

876/7

Step-by-step explanation:

Just plug the number 5 into the equation and solve. Remember your Order of Operations (PEMDAS).

4 0
2 years ago
The graph shows how a motorboat travels around a lake. What does the graph most likely show?
kozerog [31]
D, it increases then goes at a constant speed
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3 years ago
Consider a particle moving along the x-axis where x(t) is the position of the particle at time t, x' (t) is its velocity, and x'
vodka [1.7K]

Answer:

a) v(t) =x'(t) = \frac{dx}{dt} = 3t^2 -12t +9

a(t) = x''(t) = v'(t) =6t-12

b)  0

c) a(t) = x''(t) = v'(t) =6t-12

When the acceleration is 0 we have:

6t-12=0, t =2

And if we replace t=2 in the velocity function we got:

v(t) = 3(2)^2 -12(2) +9=-3

Step-by-step explanation:

For this case we have defined the following function for the position of the particle:

x(t) = t^3 -6t^2 +9t -5 , 0\leq t\leq 10

Part a

From definition we know that the velocity is the first derivate of the position respect to time and the accelerations is the second derivate of the position respect the time so we have this:

v(t) =x'(t) = \frac{dx}{dt} = 3t^2 -12t +9

a(t) = x''(t) = v'(t) =6t-12

Part b

For this case we need to analyze the velocity function and where is increasing. The velocity function is given by:

v(t) = 3t^2 -12t +9

We can factorize this function as v(t)= 3 (t^2- 4t +3)=3(t-3)(t-1)

So from this we can see that we have two values where the function is equal to 0, t=3 and t=1, since our original interval is 0\leq t\leq 10 we need to analyze the following intervals:

0< t

For this case if we select two values let's say 0.25 and 0.5 we see that

v(0.25) =6.1875, v(0.5)=3.75

And we see that for a=0.5 >0.25=b we have that f(b)>f(a) so then the function is decreasing on this case.  

1

We have a minimum at t=2 since at this value w ehave the vertex of the parabola :

v_x =-\frac{b}{2a}= -\frac{-12}{2*3}= -2

And at t=-2 v(2) = -3 that represent the minimum for this function, we see that if we select two values let's say 1.5 and 1.75

v(1.75) =-2.8125< -2.25= v(1.5) so then the function sis decreasing on the interval 1<t<2

2

We see that the function would be increasing.

3

For this interval we will see that for any two points a,b with a>b we have f(a)>f(b) for example let's say a=3 and b =4

f(a=3) =0 , f(b=4) =9 , f(b)>f(a)

The particle is moving to the right then the velocity is positive so then the answer for this case is: 0

Part c

a(t) = x''(t) = v'(t) =6t-12

When the acceleration is 0 we have:

6t-12=0, t =2

And if we replace t=2 in the velocity function we got:

v(t) = 3(2)^2 -12(2) +9=-3

5 0
3 years ago
Solve for y.<br> 8y-3y=40
Airida [17]

Answer:

8

Step-by-step explanation:

8y-3y=40

5y. = 40

y. =8

the value of y is 8.

...

5 0
3 years ago
Read 2 more answers
The data below represent the ages of people working at a store.
Slav-nsk [51]

Answer:

The first step is sort the values on increasing order and we got:

18, 18, 19, 19, 19, 20, 22, 23. 25,  26, 31

And in order to find the first quartile we can separate the first 5 lowest values from the largest 5 values. And for this case we focus on these values:

18, 18, 19, 19, 19

And if we find the median of the last 5 values we can find the first quartile and we got:

Q_1 = 19

The best answer would be:

19

Step-by-step explanation:

For this problem we have the following dataset:

18, 26, 19, 25, 19, 23, 31, 22, 19, 18, 20

The first step is sort the values on increasing order and we got:

18, 18, 19, 19, 19, 20, 22, 23. 25,  26, 31

And in order to find the first quartile we can separate the first 5 lowest values from the largest 5 values. And for this case we focus on these values:

18, 18, 19, 19, 19

And if we find the median of the last 5 values we can find the first quartile and we got:

Q_1 = 19

The best answer would be:

19

4 0
3 years ago
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