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Whitepunk [10]
2 years ago
8

2 Mae has 36 orange slices. She will fill each of

Mathematics
1 answer:
andriy [413]2 years ago
7 0

Answer:

5 with 1 left.

Step-by-step explanation: 7 goes into 36 5 times.

5x7=35

36-35=1 left over.

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Um. i just need help with this! so if anyone knows help me plz <3
kap26 [50]

Answer:

Last one

Step-by-step explanation:

You can simplify the first one or compare both of them if they have the same ratios! Hope this helps <3

6 0
3 years ago
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Parker offers to pay for 5 of his friends to play laser tag, but 3 of them don’t want to play. Parker offers to pay for 5 of his
gtnhenbr [62]

Answer: B

Step-by-step explanation:

First, you have to find how many friends are playing. This can be found in the equation 5-3. Now you multiply by six to find the cost. If you chose C, that would be incorrect, because the () you would mltilply first (30) and then subtract 3 (27). You can also think of it as finding the cost of how much all of them want to play by using the distributive property, leaving you with 30 - 18, and subtract from there to get 12.

6 0
3 years ago
Change the following into mixed fraction 13/5​
Oduvanchick [21]

Answer:

2 3/5

Step-by-step explanation:

13/5​

5 goes into 13 2 time

2*5 =10

13-10 =3

There is 3 left over.  This goes over the denominator

2 3/5

7 0
3 years ago
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Need help! What is the length of one side of the square?
scoray [572]

Answer:4

Step-by-step explanation:

6 0
3 years ago
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Suppose that 35 people are divided in a random manner into two teams in such a way that one team contains 10 people and the othe
Effectus [21]

Answer:

0.5798 or 57.98%

Step-by-step explanation:

The total number of ways to form the two teams is the combination of choosing 10 people out of 35 (₃₅C₁₀). The number of possibilities that A and B are both on the 10-people team is given by the combination of choosing 8 people (since two are fixed) out of 33 (₃₃C₈).The number of possibilities that A and B are both on the 25-people team is given by the combination of choosing 10 people out of 33 (₃₃C₈).

Therefore, the probability that two particular people A and B will be on the same team is:

P = \frac{_{33}C_8+_{33}C_{10}}{_{35}C_{10}} \\\\P=\frac{\frac{33!}{(33-8)!8!}+\frac{33!}{(33-10)!10!} }{\frac{35!}{(35-10)!10!}} \\\\P=\frac{69}{119} = 0.5798

The probability is 0.5798 or 57.98%.

8 0
3 years ago
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