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Natasha2012 [34]
3 years ago
8

1 point

Mathematics
1 answer:
Ahat [919]3 years ago
8 0

James's current balance on his credit card is <u>$900.</u>

This amount represents the card's balance before the current charge of $1,500 and the finance charge of $60.

<h3>What is a credit card balance?</h3>

A credit card balance is the amount of the charges made on a credit card, including the finance charges, and therefore, owed to a credit card company.

<h3>Data and Calculations:</h3>

Current current balance = $x

APR (Annual Percentage Rate) of interest = 30%

Monthly APR = 2.5% (30%/12)

Current purchase for the month = $1,500

Finance charge for the month = $60

Finance charge for the current purchase = $37.50 ($1,500 x 2.5%)

Finance charge for the current balance = $22.50 ($60 - $37.50)

The current balance that attracts the finance charge of $22.50 will be $900 ($22.50/2.5%).

<u>Alternatively:</u>

Since the monthly APR is 2.5% and the finance charge is $60 for the month, the balance at the end of the month is $2,400 ($60/2.5%).

Thus, the current balance on James' credit card is $900 ($2,400 - $1,500) while the end-of-the-month balance is $2,460 ($900 + $1,500 + $60).

Learn more about credit card balance at brainly.com/question/6872962

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Based on aâ poll, among adults who regret gettingâ tattoos, 18â% say that they were too young when they got their tattoos. Assum
Sergeeva-Olga [200]

Answer:

a) 20.44% probability that none of the selected adults say that they were too young to get tattoos.

b) 35.90% probability that exactly one of the selected adults says that he or she was too young to get tattoos.

c) 56.34% probability that the number of selected adults saying they were too young is 0 or 1.

d) No

Step-by-step explanation:

For each adult, there are only two possible outcomes. Either they say they were too young when they got their tattoos, or they don't say that. Each adult is independent of each other. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

18% say that they were too young when they got their tattoos.

This means that p = 0.18

Eight adults who regret getting tattoos are randomly selected

This means that n = 8

a. Find the probability that none of the selected adults say that they were too young to get tattoos.

This is P(X = 0).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{8,0}.(0.18)^{0}.(0.82)^{8} = 0.2044

20.44% probability that none of the selected adults say that they were too young to get tattoos.

b. Find the probability that exactly one of the selected adults says that he or she was too young to get tattoos.

This is P(X = 1).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 1) = C_{8,1}.(0.18)^{1}.(0.82)^{7} = 0.3590

35.90% probability that exactly one of the selected adults says that he or she was too young to get tattoos.

c. Find the probability that the number of selected adults saying they were too young is 0 or 1.

Either a. or b.

20.44 + 35.90 = 56.34

56.34% probability that the number of selected adults saying they were too young is 0 or 1.

d. It we randomly select 9 adults. Is 1 a significantly low number who day that they were too young to get tattoos?

Now n = 9

It is significantly low if it is more than 2.5 standard deviations below the mean.

The mean is E(X) = np = 9*0.18 = 1.62

The standard deviation is \sqrt{V(X)} = \sqrt{n*p*(1-p)} = \sqrt{9*0.18*0.82} = 1.15

1 > (1.62 - 2.5*1.15)

So the answer is no.

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