Answer:
At 11:00 am the both trains will be at same distance away from Roseville
Step-by-step explanation:
The first train was 40 miles away from Roseville at 7:00 am
After some time t the both trains will be at the same distance away from Roseville.
We will make equation for that situation
d- distance v1= 40mph and v2= 50mph - velocity
d = v1*t + 40 = v2*t => v2*t - v1*t = 40 => t (v2-v1) = 40 -> t = 40/ (v2-v1)
t = 40/(50-40) = 40/10= 4h t = 4h
7:00 am * 4h = 11:00 am
Good luck!!!
The probability any one system works is 0.99
So the probability of any one system failing is 1-0.99 = 0.01, so basically a 1% chance of failure for any one system
Multiply out the value 0.01 with itself four times
0.01*0.01*0.01*0.01 = 0.000 000 01
I'm using spaces to make the number more readable
So the probability of all four systems failing is 0.00000001
Subtract this value from 1 to get
1 - 0.00000001 = 0.99999999
The answer is 0.99999999 which is what we'd expect. The probability of at least one of the systems working is very very close to 1 (aka 100%)
6 inches from the original piece of ribbon is left.
The answer to your question would be -25/3
As decimal -8.333333
Answer:
the first number is 2, the second number is 9 :)
Step-by-step explanation:
brainliest? :)
