Define a function below, posodd_number_filter, which takes a single numerical argument. Complete the function to return accepted
1 answer:
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Answer:
#include<iostream>
#include<math.h>
using namespace std;
//main function
int main(){
//initialization
long b1;
int d1=0,count_pos=0;
//display the message
cout<<"Enter the binary number: ";
cin>>b1; //store the value
//loop for take the digit one by one
while(b1!=0){
int rem1 = b1%10;
d1 = d1 + rem1*pow(2,count_pos);
count_pos++;
b1 = b1/10;
}
//display the output
cout<<"The decimal number is: "<<d1<<endl;
}
Explanation:
Create the main function and initialize the variables. Then, display the message on the screen by using the instruction cout and then, store the input enter by the user into the variable. Here, the variable declares with type 'long' because of the size of the input.
After that, we take a while loop for splitting the binary number into the digits and then we can do the operation.
Let's understand how you can convert binary to decimal with an example:
let the binary number is 1001:
decimal number is [/tex]
we put the same algorithms in the code. split the number into digit and then multiply with n raised to the power of 2 here, n is the position of digit from left to right.
NOTE: Position starts from zero.
and then, add the values. this process continues until the number is not zero.
After that, display the output on the screen.