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2 years ago

20. The area of the base of a triangular prism

Mathematics

1 answer:

german2 years ago

5 0

Answer: 40 cm^3

Step-by-step explanation:

The volume of a triangular prism is the base * height.

Therefore, the volume is 50 cm^2 * 8 cm = 40 cm^3

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The standard deviation of a sample taken from population A is 17.6 for a sample of 25.

lawyer [7]

Answer:

The standard deviation of the sample mean differences is _5.23_

Step-by-step explanation:

We have a sample of a population A and a sample of a population B.

For the sample of population A, the standard deviation $\sigma_A$ is

$\sigma_A = 17.6$

The sample size $n_A$ is:

$n_A = 25$ .

For the sample of population B, the standard deviation $\sigma_B$ is

$\sigma_B = 21.2$

The sample size $n_B$ is:

$n_B = 30$ .

Then the standard deviation for the difference of means has the following form:

$\sigma=\sqrt{\frac{\sigma_A^2}{n_A}+\frac{\sigma_B^2}{n_B}}$

Finally

$\sigma=\sqrt{\frac{17.6^2}{25}+\frac{21.2^2}{30}}\\\\\sigma= 5.23$

7 0

4 years ago

Help please thank you

Ad libitum [116K]

In order for the triangle to be isosceles, we have to set two lengths of the triangle equal to each other.

Let's take the lengths 5x-12 and x+20 and set them equal to each other.

5x - 12 = x + 20

Combine like terms by moving them over to their respective sides.

Subtract x from both sides of the equation.

4x - 12 = 20

Add 12 to both sides of the equation.

4x = 32

Divide both sides by 4.

x = 8

Check your answer by substituting.

5x - 12 = x + 20

5(8) - 12 = 8 + 20

40 - 12 = 28

28 = 28

Solution: x = 8

5 0

4 years ago

The planet venus is on average 2.5x10^7 kilometers from earth. The planet mars is on average 2.25x10^8 kilometers from earth. Wh

umka21 [38]

Answer:

The average distance from venus to mars is 2.5x10⁸ kilometers.

Step-by-step explanation:

We know:

d₁: average distance between venus and earth = 2.5x10⁷ km

d₂: average distance between mars and earth = 2.25x10⁸ km

We can find the average distance from venus to mars as follows:

$d_{t} = d_{1} + d_{2}$

First, we need to equal the base power 10 so we can sum both distances:

$2.25 \cdot 10^{8} = 2.25 \cdot 10^{7} \times 10 = 22.5 \cdot 10^{7} km$

Now, average distance:

$d_{t} = 2.5 \cdot 10^{7} + 22.5 \cdot 10^{7} = (2.5 + 22.5) \cdot 10^{7} = 25 \cdot 10^{7} km = 2.5 \cdot 10^{8} km$

Therefore, the average distance from venus to mars is 2.5x10⁸ kilometers.

I hope it helps you!

6 0

3 years ago

Please help!!!! i will give brainliest

ehidna [41]

......The last one

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5 0

3 years ago

Record the length of this line shown in centimeters.

Sliva [168]

Answer:

Step-by-step explanation:

the ruler measured 12

8 0

3 years ago