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nata0808 [166]
2 years ago
8

Complete the following statement. 20% of $55 = $____

Mathematics
1 answer:
Eva8 [605]2 years ago
3 0

Answer:

$11

Step-by-step explanation:

Let's take 20% and convert it into a decimal, which is .20. Multiply that percentage by $55 (.20 * 55) and you get $11, which is the answer.

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What is the upper bound of the function f(x)=4x4−2x3+x−5?
inessss [21]

Answer:

(no global maxima found)

Step-by-step explanation:

Find and classify the global extrema of the following function:

f(x) = 4 x^4 - 2 x^3 + x - 5

Hint: | Global extrema of f(x) can occur only at the critical points or the endpoints of the domain.

Find the critical points of f(x):

Compute the critical points of 4 x^4 - 2 x^3 + x - 5

Hint: | To find critical points, find where f'(x) is zero or where f'(x) does not exist. First, find the derivative of 4 x^4 - 2 x^3 + x - 5.

To find all critical points, first compute f'(x):

d/( dx)(4 x^4 - 2 x^3 + x - 5) = 16 x^3 - 6 x^2 + 1:

f'(x) = 16 x^3 - 6 x^2 + 1

Hint: | Find where f'(x) is zero by solving 16 x^3 - 6 x^2 + 1 = 0.

Solving 16 x^3 - 6 x^2 + 1 = 0 yields x≈-0.303504:

x = -0.303504

Hint: | Find where f'(x) = 16 x^3 - 6 x^2 + 1 does not exist.

f'(x) exists everywhere:

16 x^3 - 6 x^2 + 1 exists everywhere

Hint: | Collect results.

The only critical point of 4 x^4 - 2 x^3 + x - 5 is at x = -0.303504:

x = -0.303504

Hint: | Determine the endpoints of the domain of f(x).

The domain of 4 x^4 - 2 x^3 + x - 5 is R:

The endpoints of R are x = -∞ and ∞

Hint: | Evaluate f(x) at the critical points and at the endpoints of the domain, taking limits if necessary.

Evaluate 4 x^4 - 2 x^3 + x - 5 at x = -∞, -0.303504 and ∞:

The open endpoints of the domain are marked in gray

x | f(x)

-∞ | ∞

-0.303504 | -5.21365

∞ | ∞

Hint: | Determine the largest and smallest values that f achieves at these points.

The largest value corresponds to a global maximum, and the smallest value corresponds to a global minimum:

The open endpoints of the domain are marked in gray

x | f(x) | extrema type

-∞ | ∞ | global max

-0.303504 | -5.21365 | global min

∞ | ∞ | global max

Hint: | Finally, remove the endpoints of the domain where f(x) is not defined.

Remove the points x = -∞ and ∞ from the table

These cannot be global extrema, as the value of f(x) here is never achieved:

x | f(x) | extrema type

-0.303504 | -5.21365 | global min

Hint: | Summarize the results.

f(x) = 4 x^4 - 2 x^3 + x - 5 has one global minimum:

Answer: f(x) has a global minimum at x = -0.303504

5 0
3 years ago
Read 2 more answers
Simplify <br> (3xˆ5-2)ˆ1/2
ladessa [460]

All you need to do with this problem is convert (3x^5-2)^\frac{1}{2} into a square root. Then you'll get the answer \sqrt{3x^5-2}.

3 0
3 years ago
Can somebody help me
Sergeeva-Olga [200]

cis(x)=\cos x+i\sin x\\\\cis15^o=\cos15^o+i\sin15^o\\\\\cos15^o=\dfrac{\sqrt6+\sqrt2}{4};\ \sin15^o=\dfrac{\sqrt6-\sqrt2}{4}\\\\\text{therefore}\\\\7cis15^o=7\left(\cos15^o+i\sin15^o\right)=7\cos15^o+7i\sin15^o\\\\=7\left(\dfrac{\sqrt6+\sqrt2}{4}\right)+7\left(\dfrac{\sqrt6-\sqrt2}{4}\right)i

6 0
3 years ago
On Monday, 30% of the 900 students at Maple Middle school walk to school. Complete the double numberline model. How many student
vagabundo [1.1K]

the answer is 270 (dont click ant links in this app)

8 0
2 years ago
Solve the proportion using equivalent ratios. Explain the steps you used to solve the proportion, and include the answer in your
rodikova [14]

Answer: Your answer is X=6

Step-by-step explanation:

10/3 = 20/x

Determine the defined range

10/3 20/x, x=0

Cross-multiply

10x = 60

Divide both sides by 10

x=6,x=0

Check if the solution is in the defined range

SOLUTION x=6

<u><em>I HOPE THIS HELPS IF NOT THE SORRY</em></u>

<u><em></em></u>

4 0
3 years ago
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