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givi [52]
3 years ago
13

A pole, 4m high, stands, vertically, on

Mathematics
1 answer:
Lostsunrise [7]3 years ago
6 0

Answer:

Length of the shadow of the pole is 6.93 metres

Step-by-step explanation:

Given:

Height of the pole = 4 m

The angle sun makes with the horizontal = 30 degrees

To Find:

Length of the shadow of the pole = ?

Solution:

The tangent ratio is the value received when the length of the side opposite of angle theta is divided by the length of the side adjacent to angle theta

Let x be the length of the shadow

According to the tangent ratio

tan {\theta} = \frac{opposite}{adjacent}

On substituting the values,

ta( {30^{o}) = \frac{4}{x}

x  = \frac{4}{tan ({30^{o})}}

x =\frac{4}{0.57735027}

x  = 6.93 m

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Answer:

$4600

Step-by-step explanation:

$3000 to pay off the car + $1600 to repaint the kitchen = $4600 owed on the home equity line of credit

3 0
3 years ago
Simplify this equation (3√2)²​
Scilla [17]

Answer:

18

Step-by-step explanation:

4 0
3 years ago
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The average number of accidents is 3 per month, what is the probability of 1 accident?
tatuchka [14]
<h2>Hello!</h2>

The answer is: 33.33%

<h2>Why?</h2>

Since we have the average number of accidents that occurs in 1 month, and it's equal to 3, we can calculate the probability of 1 accident occurs by dividing it into the average number of accidents, using the following formula:

Probability=\frac{FavorableOutcomes}{Outcomes}*100

Where,

Favorable outcomes are the occurrence of the event, for this case, it's equal to 1.

Outcomes are the possible occurrence of the event, for this case, it's equal to 3.

So, by substituting we have:

Probability=\frac{1}{3}*100

Probability=0.3333*100=33.33

So, the probability will be equal to 33.33%

Have a nice day!

7 0
3 years ago
OH NO!!! Madeleine’s data has been corrupted, again! Using the incomplete data file below, which she was able to recover from he
-Dominant- [34]

Answer:

a. N=25

b. X[bar]= 60.52

c. Y[bar]= 106.72

d. SSx= 115.24

e. ∑X*∑Y = 4036684

f. SSxy= 202020.3296

g. √(SSx*SSy)= 449.46

Step-by-step explanation:

Hello!

Using the attached data you need to calculate some statistics.

a) N

The sample size is listed under the first column "subject" You can see that 25 subjects qhere studied so N=25.

b.

The mean of set X is equal to X[bar]= ∑X/n= 1513/25= 60.52

∑X is listed in the second table.

c.

The mean of ser Y is Y[bar]= ∑Y/n= 2668/25= 106.72

∑Y is listed in the second table.

d.

Sum of Squares of set X SSx= ∑X²-[(∑X)²/n]= 91682-[(1513)²/25]= 115.24

e.

∑X*∑Y =1513*2668= 4036684

f.

SSxy= (∑X²-[(∑X)²/n]) * (∑Y²-[(∑Y)²/n])= (91682-[(1513)²/25]) * (286482*[(2668)²/25])= 202020.3296

g.

√(SSx*SSy)= √(115.24*1753)= 449.46

I hope you have a SUPER day!

3 0
3 years ago
What are the solution(s) of the quadratic equation 98 – x2 = 0
DanielleElmas [232]
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x^{2} = 98

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x = +/-  \sqrt{98}

The two factors that make up 98 are 49 and 2. 49 can be square rooted. So we are left with these answers:

x = - 7 \sqrt{2} and x = 7 \sqrt{2}
4 0
3 years ago
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