Answer:
The checkbook balance is $178 .7.
Step-by-step explanation:
As given
Sherry had an ending balance $ 125.36, outstanding deposits of $153.53, and outstanding checks of $100.19.
Thus
Checkbook balance = Ending balance + Outstanding deposits - Outstanding checks
Putting the values in the above
Checkbook balance = $ 125.36 + $153.53 - $100.19
= $ 278.89 - $100.19
= $ 178.7
Therefore the checkbook balance is $178 .7.
Answer:
Step-by-step explanation:
just simplify the LHS first.
You can either multiply 1/5 by (x+3) and then solve
or
multiply both sides by 5 to get rid of 1/5 on LHS
I will multiply by 5
(x+3)= -10x-15 ( 5*1/5(x+3)= -5(2x+3)
now rearrange the equation
x+3=-10x-15
-10x-15-x-3=0
-11x-17=0
-11x=17
x= -17/11
Answer:
Rational number
Step-by-step explanation:
If a number is expressed in the form of p/q then it is a rational number. Here p and q are integers, and q is not equal to 0. A rational number should have a numerator and denominator.
You can use the identity
cos(x)² +sin(x)² = 1
to find sin(x) from cos(x) or vice versa.
(1/4)² +sin(x)² = 1
sin(x)² = 1 - 1/16
sin(x) = ±(√15)/4
Then the tangent can be computed as the ratio of sine to cosine.
tan(x) = sin(x)/cos(x) = (±(√15)/4)/(1/4)
tan(x) = ±√15
There are two possible answers.
In the first quadrant:
sin(x) = (√15)/4
tan(x) = √15
In the fourth quadrant:
sin(x) = -(√15)/4
tan(x) = -√15
Answer:
The answer is below
Step-by-step explanation:
Calvin school is 2.3 miles directly south of his house. After school, he takes a bus 1.8 miles west of his school to the sport complex.
a) What is the length of a straight line between calvins house and the sports complex? Round to the nearest tenth.
b) Calvin takes piano lessons at a community music school located 3.7 miles directly north of the sports complex. What is the length of a straight line between Calvin's house and the music school? Round to the nearest tenth.
Solution:
a) Calvin school, his house and the sport complex form a right angled triangle. The hypotenuse of the right angled triangle is the length of the line between Calvin's house and the sport complex. Let the length of the line between Calvin's house and the sport complex be x.
Using Pythagoras law for right angled triangle, we get that:
x² = 2.3² + 1.8²
x² = 8.53
x = √8.53
x = 2.9 miles to the nearest tenth
b) This forms a right angled triangle with the hypotenuse = length of a straight line between Calvin's house and the music school. one side of the triangle = 1.8 miles and the other side = 3.7 - 2.3 = 1.4 miles.
Let x = length of a straight line between Calvin's house and the music school. Hence:
x² = 1.8² + 1.4²
x² = 5.2
x = √5.2
x = 2.3 miles to the nearest tenth
