Let x = speed of the first car
the second car is 12 km slower so the seconds car speed is x-12
they each drove 2 hours so 1st car = 2x
2nd car = 2(x-12)
they drove 360 km
so you have 2x + 2(x-12) = 360
solve for x
2x+2(x-12) = 360
2x + 2x-24 = 360
4x-24 = 360
4x = 384
x = 384/4
x = 96
1st car drove at 96 km per hour
slower car drove at 96-12 = 84 km per hour
Answer:
The answer is 2(the square root of 65 )
Step-by-step explanation:
Plug ( -6, 2) and (8, 10) into the distance formula and solve.
Distance = the square root of ((x2 - x1)^2 + (y2 - y1)^2))
Distance = the square root of ((8 - -6)^2 + (10 - 2)^2))
Distance = the square root of (14^2 + 8^2)
Distance = the square root of (196 + 64)
Distance = the square root of 260 which can be simplified to 2(the square root of 64)
The is the concept of algebra, the weight of the spring can be modeled by the equation;
w=0.9sqrt E
where;
=energy in joules;
thus the weight of the spring when the energy is 12 j will be:
w=0.9sqrt12
w=3.18 g
Answer:
<em>55mph
. None of the options are correct
</em>
Step-by-step explanation:
If the speed varies inversely as the time it takes to drive, then v ∝ 1/t. where;
v is the speed
t is the time taken
Hence;
v = k/t with k being the constant of proportionality.
Since it takes Kris 5 hours when driving at 55 mph, we will substitute v = 55mph and t = 5 hours. into the equation above to get the value of k as shown:
55 = k/5
Cross multiply
k = 55*5
k = 275
Hence, to calculate the speed it will Martin to drive for 5 hours, we will substitute k = 275 and t = 5 into the original equation v = k/t as shownl
v = 275/5
v = 55 mph
<em>Hence, we can conclude that Martin will also need to drive at a speed of 55mph if he wants to take 5hours.</em>
