There is no equation, nor ordered pair, so it is impossible to answer this question. I apologise.
Answer:
Θ = 46°
Step-by-step explanation:
the angle between a tangent and a radius at the point of contact is 90° , so
∠ ABO = 90°
since OB = OD ( radii of circle ) then Δ BOD is isosceles and
∠ OBD = ∠ ODB = 22°
the exterior angle of a triangle is equal to the sum of the 2 opposite interior angles.
∠ AOB is an exterior angle of the triangle , then
∠ AOB = 22° + 22° = 44°
the sum of the 3 angles in Δ AOB = 180° , then
Θ + 44° + 90° = 180°
Θ + 134° = 180° ( subtract 134° from both sides )
Θ = 46°
The answer would be 28.
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Here's my work:
Remember PEMDAS:
- Parentheses
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Also, remember to always go left to right.
(6+2)^2-4*3
Square everything in the parenthesis.
36+4-4*3
Multiply where you see a multiplication symbol from left to right.
36+4-12
Add.
40-12
Subtract.
28
Done!
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I hope I was able to guide and help you on this.
If the discriminant(b^2-4ac) is rational, then the quadratic is rational.
~ThePirc
