The set of equation that is known to have 5 and 0 as solutions is A and B.
<h3>How to solve for the system of equations.</h3>
From the graph that we have here in this question, we are supposed to identify the equations that have this point.
We can do this by tracing the lines in order to locate 5 and 0 on the grid.
When we trace the bine that has 5 and 0, We would find out that it is traceable to A and B.
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Answer:
−7(2x−11)
use distributive property
-7(2x)-7(-11)
-14x+77
Sorry i have learnt it but i can remember how to do it
Answer:
vertex : (-5/2, -53/4)
solutions: (-(5-sqrt53)/2, 0) (-(5+sqrt53)/2, 0)
Step-by-step explanation:
Answer:
5⁄18 < x
Step-by-step explanation:
Start by adding like-terms [⅓ and 2⁄9] with 9 being the Least Common Denominator [LCD]. Since 2⁄9 already has a 9 in the denominator, it does not get touched, so in order to make ⅓ a denominator of 9, we simply multiply both terms by 3, to get 3⁄9. So, adding that to 2⁄9 gives you 5⁄9, also giving you <em>5⁄9</em><em> </em><em>+</em><em> </em><em>x</em><em> </em><em>></em><em> </em><em>⅚.</em><em> </em>Now, we have to find the LCD again because we have two unlike fractions. Now, our Least Common Denominator is 18, so multiply both terms in ⅚ by 3 [15⁄18] and multiply both terms in 5⁄9 by 2 [10⁄18]. Now you have two like fractions to work with, and you can clearly see that your answer is <em>x</em><em> </em><em>></em><em> </em>5⁄18. Although the answer is written in reverse, it is still the same concept.
I am joyous to assist you anytime.
