Note: Consider the side of first triangle is TQ instead of TA.
Given:
Triangles TQM and TPN which share vertex T.
To find:
The theorem which shows that 
.
Solution:
In triangle TQM and TPN,
[Given]
[Given]
[Given]
Since two sides and their including angle are congruent in both triangles, therefore both triangles are congruent by SAS postulate.
[SAS]
Therefore, the correct option is C.
Answer:
c
Step-by-step explanation:
only 2 students were asked the question, 2 students don't represent the whole population
Answer:
-7, 7
Step-by-step explanation:
Opposites are basically two numbers that are at different sides of the number line. For example, -2 and 2 are opposites because they are the same distance away from 0 on a number line making them opposites. To make an opposite just take a positive number, and then add a negative to it. (8, -8)
15. A=7, 16. V=9, 17. D=26
Step-by-step explanation:
By using Implicit Differentiation,
d/dx (y² + xy - x²) = d/dx (11x)
d/dx (y²) + d/dx (xy) - d/dx (x²) = 11
2y * dy/dx + x * dy/dx + y - 2x = 11
dy/dx (2y + x) = 11 + 2x - y
dy/dx = (11 + 2x - y) / (2y + x).
At the point (2, 3), we have x = 2, y = 3.
=> dy/dx = (11 + 2(2) - (3)) / (2(3) + (2))
= 12 / 8 = 1.5.
P.S. Your question is weird because (2,3) is not on the graph, let me know what is the correct question thanks!
