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NeTakaya
2 years ago
15

SOMEONE PLEASE I NEED HELP Find a polynomial f(x) of degree 4 that has the following zeros. 6, 5, -4, -7 - Leave your answer in

factored form. ​

Mathematics
2 answers:
sattari [20]2 years ago
8 0

Answer:

y=(x-6)(x-5)(x+4)(x+7)

Step-by-step explanation:

<u><em>Formulate the equation of the polynomial function</em></u>

<u><em /></u>y=(x-6)(x-5)(x+4)(x+7)

<em>I hope this helps you</em>

<em>:)</em>

dexar [7]2 years ago
5 0

The formula is

\\ \rm\hookrightarrow f(x)=(x-a)(x-b)(x-x)(x-d)

\\ \rm\hookrightarrow [x^2-(a+b)x+ab][x^2-(c+d)x+cd]

So

\\ \rm\hookrightarrow [x^2-11x+30][x^2+11x+28]

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Which of the following is NOT a variation of a Pythagorean identity?​
Ipatiy [6.2K]

The expression that is not a variation of the Pythagorean identity is the third option.

<h3>What is the Pythagorean identity?</h3>

The Pythagorean identity can be written as:

sin^2(x) + cos^2(x) = 1

For example, if we subtract cos^2(x) on both sides we get the second option:

sin^2(x) = 1 - cos^2(x)

Which is a variation.

Now, let's divide both sides by cos^2(x).

sin^2(x)/cos^2(x) + cos^2(x)/cos^2(x) = 1/cos^2(x)\\\\tan^2(x) + 1 = sec^2(x)\\\\tan^2(x) - sec^2(x) = -1

Notice that the third expression in the options looks like this one, but the one on the right side is positive. The above expression is in did a variation of the Pythagorean identity, then the one written in the options (with the 1 instead of the -1) is incorrect, meaning that it is not a variation of the Pythagorean identity.

Concluding, the correct option is the third one.

If you want to learn more about the Pythagorean identity, you can read:

brainly.com/question/24287773

3 0
2 years ago
What is the average velocity between 12.00 and 15.00 seconds
bekas [8.4K]

The average between 12.00 and 15.00 seconds
can be defined in a few different ways.

Way #1:  (speed)

     Average speed =
         (1/2) (the speed at 12 seconds  +  the speed at 15 seconds) .


Way #2:  (speed)

   Average speed =
       (1/3) (the distance covered between 12.00 and 15.00 seconds)


Way #3:  (velocity)

   Average velocity =
     (1/3) (distance between location at 12 sec and location at 15 sec)
       in the direction from location at 12 sec to location at 15 sec.


That's the best we can do with the combination of given and
not given information in the question.

3 0
3 years ago
Read 2 more answers
Suppose it is known that 60% of radio listeners at a particular college are smokers. A sample of 500 students from the college i
vladimir1956 [14]

Answer:

The probability that at least 280 of these students are smokers is 0.9664.

Step-by-step explanation:

Let the random variable <em>X</em> be defined as the number of students at a particular college who are smokers

The random variable <em>X</em> follows a Binomial distribution with parameters n = 500 and p = 0.60.

But the sample selected is too large and the probability of success is close to 0.50.

So a Normal approximation to binomial can be applied to approximate the distribution of X if the following conditions are satisfied:

1. np ≥ 10

2. n(1 - p) ≥ 10

Check the conditions as follows:

 np=500\times 0.60=300>10\\n(1-p)=500\times(1-0.60)=200>10

Thus, a Normal approximation to binomial can be applied.

So,  

X\sim N(\mu=600, \sigma=\sqrt{120})

Compute the probability that at least 280 of these students are smokers as follows:

Apply continuity correction:

P (X ≥ 280) = P (X > 280 + 0.50)

                   = P (X > 280.50)

                   =P(\frac{X-\mu}{\sigma}>\frac{280-300}{\sqrt{120}}\\=P(Z>-1.83)\\=P(Z

*Use a <em>z</em>-table for the probability.

Thus, the probability that at least 280 of these students are smokers is 0.9664.

8 0
2 years ago
B. (4,-7)
zvonat [6]

Answer:

b)-3

c)17

d)-11

Step-by-step explanation:

4,-7)

-3

5 0
3 years ago
When lava is expelled from a volcano, it temperature may vary from 700 degrees Celsius to 1200 degrees Celsius. Write an absolut
ValentinkaMS [17]

Answer:

Ix - 950°C I ≤ 250°C

Step-by-step explanation:

We are told that the temperature may vary from 700 degrees Celsius to 1200 degrees Celsius.

And that this temperature is x.

This means that the minimum value of x is 700°C while maximum of x is 1200 °C

Let's find the average of the two temperature limits given:

x_avg = (700 + 1200)/2 =

x_avg = 1900/2

x_avg = 950 °C

Now let's find the distance between the average and either maximum or minimum.

d_avg = (1200 - 700)/2

d_avg = 500/2

d_avg = 250°C.

Now absolute value equation will be in the form of;

Ix - x_avgI ≤ d_avg

Thus;

Ix - 950°C I ≤ 250°C

3 0
2 years ago
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