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aev [14]
2 years ago
15

Please help it’s very urgent and I need the right answer

Mathematics
1 answer:
8090 [49]2 years ago
3 0

Answer:

3x + 15 = 3*10 + 15 = 30 + 15 = 45

<u>3x + 15 = 45</u>

Now,

2x + 25 = 2*10 + 25 = 20 + 25 = 45

<u>2x + 25 = 45</u>

Step-by-step explanation:

3x + 15 + 2x + 25 = 90

or, 5x + 40 = 90

or, 5x = 90 - 40

so, 5x = 50

so, x = 50/5 = 10

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Please help I don’t understand
Olegator [25]

Answer:

They are not similar.

Step-by-step explanation:

To find whether or not they are similar, set them up as a proportion.

(2.4/5.2) = (8/13)

Now cross multiply.

2.4*13 = 5.2*8

31.2 = 41.6

Since they are not exact, they are not similar.

8 0
3 years ago
PLEASE HELP ASAP! I WILL GIVE BRAINLIEST!
olga_2 [115]
In 75 minutes you travelled 30 kilometers, so the rate is 30/75=0.4km/minute

another way is to use the two points to find the slope: m=(30-0)/(75-0)=0.4
6 0
3 years ago
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How many solutions does 5x - 4x = 2x + 6 have
LUCKY_DIMON [66]

i think one which is where x=-6

8 0
2 years ago
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Please help me!!!! You only have to answer number 1!!!
mrs_skeptik [129]

Given : A social media website has currently = 1,000 members.

           In each month number of members gets triple.

To find: Equation that represents number of members m belongs to site.

Solution: Because we are given, each month the number of members gets triple, that means each month we can multiply by 3 to the number of members of previous month.

For first month, we would multiply 1,000 by 3.

For second month, we would multiply 1,000 by 3 *3.

For second month, we would multiply 1,000 by 3*3*3.

Each month one factor of 3 is being increasing.

We could write those 3's as exponents of 3.

Like 1000*3 = 1000*3^1

1000 * 3^2.

1000 * 3^3.

As many months as many 3's are there.

So, the exponent of 3 is represnts the number of months.

Let us take a variable for number of month by n.

So, we could setup an equation for number of members m belongs to site on a particular month n as

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7 0
3 years ago
Using the digits 2 through 8, find the number of different 5-digit numbers such that, digits can be used more than once.
Solnce55 [7]

Answer:

7 digits can be used for each position

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N = 7^5 = 16,807 numbers

You have 7 choices for the first position, second position, etc.

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