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3 years ago

Can someone help me finish all of these? no steps are needed. if i could have the answers then that would be amazing.

Mathematics

2 answers:

PilotLPTM [1.2K]3 years ago

8 0

Answer:

1.7 8 3 6 2

2.10 5 6 3 9

3.11 10 4 6 7

4.7 4 1 9 4

5.1 6 3 8 9

6.10 2 5 6 8

7.8 6 4 10 7

8. 5 6 3 4 9

9.1 4 8 5 9

10.9 4 3 7 4

Step-by-step explanation:

expeople1 [14]3 years ago

7 0

1: -10, -19, -22, -19, -10

2: -15, -3, 1, -3, -15

3: -30, -9, -2, -9, -30

4: -1, -16, -21, -16, -1

5: 7, 25, 30, 25, 7

6: -31, -9, 1, -1, -15

7: -38, -11, -2, -11, -38

8: -3, 0, 1, 0, -3

9: 13, 7, 5, 7, 13

10: 60, 30, 20, 30, 60

I spent half an hour on this... Brainly would be appreciated

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The answer is (1+0.18)16.

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Given the line with equation 7 − 2 = 8,

timurjin [86]

Hey there!!

The basic slope-intercept formula :

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3 years ago

Fill in the boxes below with the numbers 1-5.

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Answer:

4 - 2 - 3 - 1 - 5

Step-by-step explanation:

The substitute method consists of the following steps:

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3 years ago

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An urn contains 5 white and 10 black balls. A fair die is rolled and that number of balls is randomly chosen from the urn. What

galina1969 [7]

Answer:

Part A:

The probability that all of the balls selected are white:

$P(A)=\frac{1}{6}(\frac{1}{3}+\frac{2}{21}+\frac{2}{91}+\frac{1}{273}+\frac{1}{3003}+0)\\ P(A)=\frac{5}{66}=0.075757576$

Part B:

The conditional probability that the die landed on 3 if all the balls selected are white:

$P(D_3|A)=\frac{\frac{2}{91}*\frac{1}{6}}{\frac{5}{66} } \\P(D_3|A)=\frac{22}{455}=0.0483516$

Step-by-step explanation:

A is the event all balls are white.

D_i is the dice outcome.

Sine the die is fair:

$P(D_i)=\frac{1}{6}$ for i∈{1,2,3,4,5,6}

In case of 10 black and 5 white balls:

$P(A|D_1)=\frac{5_{C}_1}{15_{C}_1} =\frac{5}{15}=\frac{1}{3}$

$P(A|D_2)=\frac{5_{C}_2}{15_{C}_2} =\frac{10}{105}=\frac{2}{21}$

$P(A|D_3)=\frac{5_{C}_3}{15_{C}_3} =\frac{10}{455}=\frac{2}{91}$

$P(A|D_4)=\frac{5_{C}_4}{15_{C}_4} =\frac{5}{1365}=\frac{1}{273}$

$P(A|D_5)=\frac{5_{C}_5}{15_{C}_5} =\frac{1}{3003}=\frac{1}{3003}$

$P(A|D_6)=\frac{5_{C}_6}{15_{C}_6} =0$

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The probability that all of the balls selected are white:

$P(A)=\sum^6_{i=1} P(A|D_i)P(D_i)$

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Part B:

The conditional probability that the die landed on 3 if all the balls selected are white:

We have to find $P(D_3|A)$

The data required is calculated above:

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Can someone help me finish all of these? no steps are needed. if i could have the answers then that would be amazing.​

Can someone help me finish all of these? no steps are needed. if i could have the answers then that would be amazing.