Can someone help me finish all of these? no steps are needed. if i could have the answers then that would be amazing.
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State the vertex and axis of symmetry of the graph of y=ax^2+c
General form of quadratic equation is
There is no bx in our given equation, so we put 0x
Given equation can be written as
a=a , b=0
Now we use formula to find vertex
Now we plug in 0 for 'a' and find out y
So our vertex is (0,c)
The axis of symmetry at x coordinate of vertex
So x=0 is our axis of symmetry