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Nitella [24]
3 years ago
11

I need help I will mark BRAINLIEST!!!!

Mathematics
2 answers:
Arte-miy333 [17]3 years ago
7 0

Answer: 6.2x10^10

Step-by-step explanation:

There must be a number less than 10 on the left side

Diano4ka-milaya [45]3 years ago
7 0

Answer:

Option 3

Step-by-step explanation:

Because 6.2 x 10^7 using the caret symbol

You might be interested in
Whats 15-b=4b-5(5-3)
Gala2k [10]

15-b=4b-5(5-3)

Multiply the bracket by -5

(-5)(5)=-25

(-5)(-3)=15

15-b=4b-25+15

15-b=4b-10

Move 15 to the other side

Sign changes from +15 to -15

15-15-b=4b-10-15

-b=4b-25

Move 4b to the other side.

-b-4b=4b-4b-25

-b-4b=-25

-5b=-25

divide both sides by -5

-5b/-5=-25/-5

Answer: b=5

5 0
3 years ago
Yo i need the answer
klemol [59]

Answer:

c

Step-by-step explanation:

im pretty sure an additive inverse is just the absolute value

5 0
3 years ago
Please help please please help
aleksklad [387]

Answer:

Step-by-step explanation:

<u><em>   Number    </em></u><em>         </em><u><em>   Estimate using a single digit and power of 10  </em></u>

23,898,497                      2 × 10⁷          

0.000136                          1 × 10⁻⁴

26,857                              3 × 10⁴

0.0302                             3 × 10⁻²

3 0
2 years ago
Solve the inequality of -4p &lt; 2/3
andrezito [222]
Just divide both sides by -4. Since you are dividing with a negative number, you will also have to flip the greater than sign.

p > -1/6
4 0
2 years ago
1. Alicia has 7 paintings she wants to hang side by side on her wall.
Kipish [7]

A.

If we take 7 paintings to be hung in 7 spaces side by side, the first space can have any one of the 7 paintings, the second space can have any one of the remaining 6 paintings (as 1 is already hung), the third space can have any one of the remaining 5 paintings (as 2 already hung)...It goes on like this.

So we have 7*6*5*4*3*2*1=5040 ways to arrange all the paintings from left to write. <em>(in factorial notation it is 7!=5040)</em>

B.

We use combinations rather than permutations because order doesn't matter. If we name the paintings A,B,C,D,E,F, and G, groups of 3 paintings of ABC or ACB are the same. So we evaluate 7C3 using the combination formula,

nCr=\frac{n!}{(n-r)!r!}

We have,

7C3=\frac{7!}{(7-3)!*3!} = \frac{7!}{4!*3!} = 35

C.

This is similar to part A in some ways. Any 3 pictures can be arranged in 3! different ways. 3!=3*2*1=6. So, 6 different ways.


ANSWER:

A) 5040 ways

B) 35 different groups

C) 6 ways

8 0
3 years ago
Read 2 more answers
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