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2 years ago

Solve for d. 41 = 12 d _ 7 d

Mathematics

1 answer:

ICE Princess25 [194]2 years ago

3 0

Answer:

$d=4$

Step-by-step explanation:

$41=12d-7$

In this scenario we need to isolate the variable.

Start by adding 7 to both sides:

$41+7=12d-7+7$

$48=12d$

Divide both sides by 12:

$\frac{48}{12}=\frac{12d}{12}$

$d=4$

Substitute 4 for d to check our answer:

$41=12d-7\\41=12(4)-7\\41=48-7\\41=41\rightarrow\text{correct!}$

Therefore the answer is:

$d=4$

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Find the scale factor of the small triangle to the large triangle.

Korvikt [17]

Answer:

scale factor is: 2.25

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3 years ago

Ennifer has as many pictures on her camera as Luisa does. Jennifer has 28 pictures on her camera. How

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28 + 28 = 56 pictures have Jennifer and Louisa in all.

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2 years ago

Help me I need the answer ASAP ! Aundrea painted the background of a square mural on the wall using 138ft^2 of paint .which meas

Klio2033 [76]

Hey there! I'm happy to help!

Since this mural is a square, all the sides are the same. This means that you square on of the sides to get the area (multiply it by itself). If we have the area and want to find a side, we just go backwards and use something called the square root!

If we plug this into our calculators...

√138≈11.74734

We see that is closest to B. 12 ft.

You could also figure this out without a calculator. 138 is very close to 144, which is 12². All the other answer options are way too big.

Have a wonderful day! :D

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3 years ago

Answer the question in the picture

nekit [7.7K]

Recall the angle sum identities:

$\sin(x+y)=\sin x\cos y+\cos x\sin y$

$\cos(x+y)=\cos x\cos y-\sin x\sin y$

Now,

$\tan(x+y)=\dfrac{\sin(x+y)}{\cos(x+y)}=\dfrac{\sin x\cos y+\cos x\sin y}{\cos x\cos y-\sin x\sin y}$

Divide through numerator and denominator by $\cos x\cos y$ to get

$\tan(x+y)=\dfrac{\tan x+\tan y}{1-\tan x\tan y}$

Next, we use the fact that $x,y$ lie in the first quadrant to determine that

$\sin x=\dfrac12\implies\cos x=\sqrt{1-\sin^2x}=\dfrac{\sqrt3}2$

$\cos y=\dfrac{\sqrt2}2\implies\sin x=\sqrt{1-\cos^2x}=\dfrac1{\sqrt2}$

So we then have

$\tan x=\dfrac{\sin x}{\cos x}=\dfrac{\frac12}{\frac{\sqrt3}2}=\dfrac1{\sqrt3}$

$\tan y=\dfrac{\sin y}{\cos y}=\dfrac{\frac1{\sqrt2}}{\frac{\sqrt2}2}=1$

Finally,

$\tan(x+y)=\dfrac{\frac1{\sqrt3}+1}{1-\frac1{\sqrt3}}=\dfrac{1+\sqrt3}{\sqrt3-1}=2+\sqrt3\approx3.73$

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2 years ago

Line khas a slope of 2/3. If line m is parallel to line k, then it has a slope of

storchak [24]

Since line m is parallel to line k.

Their slopes are equal.

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So; Slope of line m=2/3

Hope it helps...

Regards;

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3 years ago