4 years ago

Find the first, fourth, and tenth terms of the arithmetic sequence described by the given rule

1 answer:

5 0

$\bf \begin{array}{lll} \stackrel{n}{location}&term&\stackrel{12+(n-1)3}{value}\\ \cline{1-3} 1&A(1)&12+(1-1)3\\ &&12\\\\ 4&A(4)&12+(4-1)3\\ &&21\\\\ 10&A(10)&12+(10-1)3\\ &&39 \end{array}$

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