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zhenek [66]
3 years ago
10

Students in 10th and 11th grade were asked whether they have a job. The raw data was converted to relative frequencies and recor

ded in the table below. A 4-column table with 3 rows. The first column has no label with entries job, no job, total. The second column is labeled tenth grade with entries 0. 14, 0. 86, 1. The third column is labeled eleventh grade with entries 0. 25, 0. 75, 1. The fourth column is labeled total with entries 0. 20, 0. 80, 1. Given the conditional relative frequency table by column, what does the 0. 14 represent? Given that a student is a 10th grader, there is a 14% chance he or she has a job. Given that a student has a job, there is a 14% chance he or she is a 10th grader. 14% of the students surveyed are 10th graders who have a job. 14% of the students are 10th graders.
Mathematics
1 answer:
Step2247 [10]3 years ago
3 0

Option A is correct. 0.14 represents that if a student is a 10th grader, there is a 14% chance he or she has a job.

it is given that there is a column with 4 column and 3 rows.

<h3>what is a conditional relative frequency table?</h3>

it is a special type of frequency table that shows relationships between two categories.

from the attached table it is clear that 0.14 is the probability of getting a job if a student is a 10th grader,

option B is incorrect, stating there is a 14% chance a student is a 10th grader if he/she has had a job since we do not know the number of students.

option C is also incorrect stating that 14% of the students surveyed are 10th graders who have a job since we do not know the total number of students.

option D is also incorrect because we do not know the number of students.

therefore, option A is correct. 0.14 represents that if a student is a 10th grader, there is a 14% chance he or she has a job.

to get more about conditional relative frequency-related problems, refer to the link,

brainly.com/question/22728236

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Answer:

There is a significant difference between the two proportions.

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for difference between population proportions is:

CI=(\hat p_{1}-\hat p_{2})\pm z_{\alpha/2}\times\sqrt{\frac{\hat p_{1}(1-\hat p_{1})}{n_{1}}+\frac{\hat p_{2}(1-\hat p_{2})}{n_{2}}}

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Compute a 90% confidence interval for the difference between the proportions of women in these two fields of engineering as follows:

CI=(\hat p_{1}-\hat p_{2})\pm z_{\alpha/2}\times\sqrt{\frac{\hat p_{1}(1-\hat p_{1})}{n_{1}}+\frac{\hat p_{2}(1-\hat p_{2})}{n_{2}}}

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There will be no difference between the two proportions if the 90% confidence interval consists of 0.

But the 90% confidence interval does not consists of 0.

Thus, there is a significant difference between the two proportions.

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