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kogti [31]
2 years ago
9

A beautiful cake was presented at a wedding reception. The cake measured 13.5 inches tall, including the decorative icing on top

that is one inch thick. If each of the six cake layers measures 1.25 inches tall, how thick is the icing between the layers? Select an Answer A 1 fourth inches B 1 half inches C 2 over 3 inches D 3 over 4 inches E 1 inch
Mathematics
1 answer:
Schach [20]2 years ago
5 0

Using proportions, it is found that the thickness of the icing between the layers, in inches, is of:

E 1 inch

<h3>What is a proportion?</h3>

A proportion is a fraction of a total amount.

In this problem, there are six layers, each measuring 1.25 inches tall, hence the height of these layers is:

6 x 1.25 = 7.5 inches

Then the height of the icing between the layers is of:

13.5 - 7.5 = 6 inches

Six layers, hence each icing is of:

6/6 = 1 inch

More can be learned about proportions at brainly.com/question/24372153

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Write an exponential function of the form f(x) = ab* whose graph passes through the
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Answer:

Step-by-step explanation:

let f(x)=ab^x

when x=1,f(x)=6

6=ab

when x=2,f(x)=18

18=ab^2

divide

\frac{ab^2}{ab}=\frac{18}{6}\\b=3\\ab=6\\3a=6\\a=2\\f(x)=2(3)^x

4 0
3 years ago
Determine what type of decimal number each fraction converts to.
Y_Kistochka [10]
A: .44 (not repeating)
b: also .444 (repeating)
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3 0
3 years ago
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ANSWER ASAP PLZ
Anit [1.1K]
So since 4 was added to x then 2 subtracted from y, to reverse it

minus 4 from x and add 2 to y

(x,y)
(5,-3)
minus 4 and add 2
(1,-1) is the reverse translated

answer is last one
3 0
3 years ago
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The answer to this.
Readme [11.4K]

Answer:

The two column proof is presented as follows;

Step {}     Statement               Reason

1 {}            \overline {AC} ≅ \overline {BD}                Given

{}              ∠CAB ≅ ∠DBA  

2  {}          \overline {AB} ≅ \overline {AB}                Reflexive property

3 {}          ΔABC ≅ ΔBAD        SAS rule of congruency

Step-by-step explanation:

Given that we have;

Segment \overline {AC} of ΔABC being congruent to (≅) segment  \overline {BD} on ΔBAD and angle ∠CAB on ΔABC is congruent to angle ∠DBA on ΔBAD, and also that the two triangles share a common side, which is segment \overline {AB}, we have;

Segment \overline {AB} is congruent to itself by reflexive property, therefore;

Two sides and an included angle on ΔABC are congruent to the corresponding two sides and an included angle on ΔBAD, which by Side-Angle-Side, SAS, rule of congruency, ΔABC is congruent to ΔBAD

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The figure attached shows the graph of the function with the two asympotes.
The formulae of those asympotes are:
y = 3, and x = 2.

This is how you work to find them.

1) The function will have vertical asympotes where the limit grows indefinetly (approach +/- ∞).

2) That happens for x = 2, where the function is not defined but it grows indefinetly toward infinity (if you come from the right side) or toward negative infinity (if you come from the left side). So, the vertical asymptote is the line x = 2.

3) The function will have a horizontal asymptote if the function tends to a constant value as x approaches infinity or negative infinity.

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That results in one horizontal asymptote which is y = 3.

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3 years ago
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