Divide the following numbers. -45/-5 = what th answer

Assume that the radius rr of a sphere is expanding at a rate of 19 in./min.19 in./min. The volume of a sphere is V=43πr3V=43πr3.

djverab [1.8K]

Answer:

$744876\pi in^3/min$ .

Step-by-step explanation:

We are given that

$\frac{dr}{dt}=19 in/min$

Volume of sphere= $\frac{4}{3}\pi r^3$

$r=4 at t=0$

$dr=19 dt$

Integrating on both sides then we get

$r=19 t+C$

Substitute r=4 and t=0

$4=C$

$r=19t+4$

$\frac{dV}{dt}=4\pi r^2\frac{dr}{dt}$

$\frac{dV}{dt}=4\pi (19t+4)^2(19)$

Substitute t=5

$\frac{dV}{dt}=4\pi (19(5)+4)^2(19)$

$\frac{dV}{dt}=4 \pi (99)^2 (19)=744876\pi in^3/min$

Hence, the volume is changing at the rate of $744876\pi in^3/min$ .

7 0

3 years ago

Solving trig equations

Anon25 [30]

Answer:

im not sure sorry

Step-by-step explanation:

also you can just search it up:)

4 0

3 years ago

Consider the volume of the region shown below, which shows a right circular cone with top radius 3 cm and height 10 cm. We have

koban [17]

I have the same problem here with a slight change in the given values:

radius is 2 & height of 6 indicates the bounding line is y = 3 x---> x = y / 3....

thus the [ π radius ² thickness ] yields π (y² / 9 ) dy , y in [ 0 , 6 ] for the volume... 

a Riemann sum is then : y_i = 0 + i [ 6 / n ] = 6 i / n , i = 1,2,3...n and do a right side sum

π Σ { i = 1,2,3..n } [ 36 i² / 9 n² ] [ 6 / n ]

I hope my guide has come to your help. God bless and have a nice day ahead!

5 0

3 years ago

What is the area of a shape with points a 5 -8 b 11, -8 c 11,0 d 6,-3 e 4,-3

Dmitriy789 [7]

Answer:

Area of the given figure is 51.5 square units.

Step-by-step explanation:

Area of rectangle OCBH = Length × width

= 11 × 8

= 88 square units

Area of trapezoid OGEF = $\frac{1}{2}(b_1+b_2)\times h$