Let's find the derivative of that hyperbola in order to find a slope formula to help us with this equation. We already have an x and y value. The derivative is found this way: 
so 
. The derivative supplies us with the slope formula we need to write the equation. Sub in the x value of 3 to find what the slope is: 
. So in our slope-intercept equation, x = 3, y = 1, and m = -1/3. Use these values to solve for b. 
so b = 2. The equation, then, for the line tangent to that hyperbola at that given point is 
Please answer this question!!! I am only in 4th grade and I need help!!!
1 answer:
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Answer:
( , 0 )
Step-by-step explanation:
Given the 2 equations
4x + 3y = 2 → (1)
2x - 3y = 1 → (2)
Adding (1) and (2) term by term will eliminate the y- term, that is
6x = 3 ( divide both sides by 6 )
x = =
Substitute x = into either of the 2 equations and evaluate for y
Substituting into (1)
4( ) + 3y = 2
2 + 3y = 2 ( subtract 2 from both sides )
3y = 0 ⇒ y = 0
Solution is ( , 0 )