Answer:
Four
Step-by-step explanation:
Let's expand and see how many nonzero terms:
⇒ (x+4)(2x²+3x+9)-3(x³-2x²+7x)=
⇒ 2x³ + 3x² + 9x + 8x² + 12 + 36 - 3x³ + 6 x² - 21 x=
⇒ - x³ + 17x² - 12x + 12
As we see the expression has four nonzero terms
Answer: root18
Step-by-step explanation:
A (2,2) x1=2 y1=2
B (5,5) x2=5 y2=5
D(AB) = root [(x2-x1)^2 + (y2-y1)^2]
= root [(5-2)^2 + (5-2)^2]
= root [3^2 + 3^2]
= root (9+9)
D(AB)=root18
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Answer:
633
Step-by-step explanation:
We have the equation
![15+102[12-(12-3*2)]+6\\\\15+102[12-(12-6)]+6\\\\15+102[12-(6)]+6\\\\15+102[6]+6\\\\15+612+6\\\\633](https://tex.z-dn.net/?f=15%2B102%5B12-%2812-3%2A2%29%5D%2B6%5C%5C%5C%5C15%2B102%5B12-%2812-6%29%5D%2B6%5C%5C%5C%5C15%2B102%5B12-%286%29%5D%2B6%5C%5C%5C%5C15%2B102%5B6%5D%2B6%5C%5C%5C%5C15%2B612%2B6%5C%5C%5C%5C633)
Answer:
s = 11
Step-by-step explanation:
Given
= 22 ← substitute r = 242
= 22 ( multiply both sides by s )
242 = 22s ( divide both sides by 22 )
11 = s
I can't see the whole problem
