Answer:
The 99% confidence interval would be given by (0.054;0.154)
. So we are confident at 99% that the true proportion of people that they did work at home at least once per week is between 0.054 and 0.154
Step-by-step explanation:
For this case we can estimate the population proportion of people that they did work at home at least once per week with this formula:
We need to find the critical value using the normal standard distribution the z distribution. Since our condifence interval is at 99%, our significance level would be given by and . And the critical value would be given by:
The confidence interval for the mean is given by the following formula:
If we replace the values obtained we got:
The 99% confidence interval would be given by (0.054;0.154)
. So we are confident at 99% that the true proportion of people that they did work at home at least once per week is between 0.054 and 0.154
Answer:
Step-by-step explanation:
I may get this wrong because I don't think it's clear enough.
3 Letters
The station call letters must start with 1 of 3 letters
3
The next letter must be one of 25 and the last letter is 24
3 * 25 * 24 = 1800
5 letters
3 * 25 * 24 * 23* 22 = 910800
Total 1800 + 910800 = 912600
41> 6m-7.
So, I added 7 to both sides and got 48>6m and then divided both sides by 6 to get 8>m or m<8.
Write it as a mixed fraction 7/5 = 1 2/5
Answer: Answer:
Its sad that you have to uses this app to get the right answers.
Have you ever stopped to ponder if someone is trying to scam/Catfish you?
Also I bet that you haven't even tried reading this question.
I know that you can do it yourself!
If not then, Sorry to hear.
Also
The answer is:
Do it yourself, Because if you try..You'll have a better answer then I ever could. Or anyone TBH