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mart [117]
2 years ago
8

How do i graph y=1/2+4

Mathematics
2 answers:
MaRussiya [10]2 years ago
8 0

Answer:

To graph the equation of a line written in slope-intercept (y=mx+b) form, start by plotting the y-intercept, which is the b value. The y-intercept is where the line will cross the y-axis, so count up or down on the y-axis the number of units indicated by the b value. From the y-intercept point, use the slope to find a second point. The numerator of the slope tells you how many units to move up or down from the intercept, and the denominator of the slope tells you how many units to move left or right in order to plot the second point. Connect the two points and draw arrows at either end to indicate that the line extends infinitely.

Step-by-step explanation:

Since the equation is in y=mx+B form, M is the value of we can use B as the Y_Intercept and M as the slope.

#LearningIsFun

galben [10]2 years ago
5 0

y=1/2+4

y=2+4

y=6

or

y=1/2+4

y=1/6

y=6

Those homeworks are so easy lmaøoo

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Sveta_85 [38]
It's basic subtraction. you subtract 7 1/8 with 4 4/8 by turning one of the one from the seven to 8/8 and add that to 1/8 so you get 9/8. Then 6 9/8 - 4 4/8 = 2 5/8.
5 0
3 years ago
Write the equation of a line that passes through two points (-1, 0) and (4, -5).
sleet_krkn [62]

Answer:

<u>y = -1 (x) -1</u>

Step-by-step explanation:

If you plug in the numbers from the coordinates into the equation, you will find that it's true.

-1 is x and 0 is y. Plug in the #s like so:

y = -1 (x) -1

0 = -1 (-1) - 1

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Therefore, the equation above represents the line that passes through both these points.

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3 years ago
How do you write the logarithmic equation in exponential form when you use ln?
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2 years ago
Suppose heights of seasonal pine saplings are normally distributed and have a known population standard deviation of 17 millimet
Mumz [18]

Answer:

296.693\leq x\leq 319.307

Step-by-step explanation:

The confidence interval for the population mean x can be calculated as:

x'-z_{\alpha /2}\frac{s}{\sqrt{n} } \leq x\leq x'+z_{\alpha /2}\frac{s}{\sqrt{n} }

Where x' is the sample mean, s is the population standard deviation, n is the sample size and z_{\alpha /2} is the z-score that let a proportion of \alpha /2 on the right tail.

\alpha is calculated as: 100%-99%=1%

So, z_{\alpha/2}=z_{0.005}=2.576

Finally, replacing the values of x' by 308, s by 17, n by 15 and z_{\alpha /2} by 2.576, we get that the confidence interval is:

308-2.576\frac{17}{\sqrt{15} } \leq x\leq 308+2.576\frac{17}{\sqrt{15} }\\308-11.307 \leq x\leq 308+11.307\\296.693\leq x\leq 319.307

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3 years ago
What is the area of triangle ABC Round to the nearest tenth of a square unit
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Where’s the triangle, isn’t there supposed to be a picture with the question

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3 years ago
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