Answer:
A. 1/5k - 2/3j and -2/3j +1/5k
Step-by-step explanation:
A. 1/5k - 2/3j and -2/3j +1/5k
B. 1/5k - 2/3j and -1/5k +2/3j
There is a change in the signs of each term
1/5k changed to -1/5k
-2/3j changed to +2/3j
Not equivalent
C. 1/5k - 2/3j and 1/5j - 2/3k
There is a change in the variables
1/5k changed to 1/5j
-2/3j changed to -2/3k
D. 1/5k - 2/3j and 2/3j - 1/5k
The is a change in the signs of each term
1/5k changed to -1/5k
-2/3j changed to +2/3j
The only equivalent expression is
A. 1/5k - 2/3j and -2/3j +1/5k
M=change in y/change in x
Finding gradient of the orginal line
=3+1/0-3
=-4/3
Since parallel lines are equal the other line would be -4/3 (gradient)
Sub (-3;2) into y=mx+c
2=-4/3 (-3)+c
2=4+5
2-4=c
-2 = c
Therefore sub all your info and you get y= -4/3x-2
This may look a little confusing but all you have to do is plug the equation given for h(x) which is 2x-5 in to the h(x) area in the equation where it says h(x) + g(x).
So far that’s (2x-5) + g(x)
Then,
Do the same with equation given for g(x) which is now,
(2x-5) + (3x+1)
Then solve,
2x - 5 + 3x + 1
2x + 3x- 5 + 1
5x - 4
Therefore the answer is 5x - 4.
Answer:
2.3
Step-by-step explanation:
so the 7.0 gets dived by the 3 because the radius is half of the circle.
Answer:
9
Step-by-step explanation:
f(-3)=-3×-3
= (-)(-)9
=+9
- into - covert into positive when you have square on x
hopefully, it works for you
