2 years ago

Positional number system where the value of a digit is determined by its location

Mathematics

1 answer:

Mama L [17]2 years ago

6 0

Hey what’s your going to

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Binary go 01000100 01001111 00100000 01100001 01101110 01111001 00100000 01101111 01100110 00100000 01111001 01101111 01110101 0

nexus9112 [7]

I d k what this is but okay

3 0

2 years ago

Write the product using exponents. 2⋅2⋅2⋅n⋅n Using exponents, the product is ?

Blababa [14]

The answer is 8n^2

2x2 is 4 x 2 is 8 two n variables so multiple it by 2 and you get your answer

3 0

2 years ago

7-x=-2 find the variable

nevsk [136]

Answer:

Step-by-step explanation:

7-x=-2

-x=-2-7

-x=-9

x=9

7 0

2 years ago

Given: AC and AE are common external tangents of G and D. BC= 123 GB=20 and AG=101. What is the measure of AC?

Solnce55 [7]

Answer:

The length of AC is 222 units.

Step-by-step explanation:

Given AC and AE are common external tangents of G and D.

BC= 123 , GB=20 and AG=101.

We have to find the measure of AC.

As, a straight line joined from the center i.e radius is perpendicular to tangent drawn. Therefore,

In ΔABG, by Pythagoras theorem

$AG^2=AB^2+BG^2$

⇒ $101^2=AB^2+20^2$

⇒ $AB^2=10201-400=9801$

⇒ AB=99 units.

Hence, AC=AB+BC=99+123=222 units.

The length of AC is 222 units.

8 0

2 years ago

Which statement is true about point F? a.F is the midpoint of AA' because bisects AA'. b.F is the midpoint of EG because AA' bis

Dimas [21]

Answer:

The correct option is;

a. F is the midpoint of $\overline{AA'}$ because line $\overline{EG}$ bisects $\overline{AA'}$

Step-by-step explanation:

Here, since we have that the triangle is reflected across EG therefore the location of the point F which is along EG bisects the line $\overline{AA'}$ as the dimensions of the line from A to F must be equal to the dimension of the line that extends from A' to F

Therefore the point F is the midpoint of $\overline{AA'}$ because line $\overline{EG}$ bisects $\overline{AA'}$ .

7 0

3 years ago