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Naily [24]
2 years ago
7

Find the area of a triangle bounded by the x-axis the line f(x)=5-5/3x and the line perpendicular to f(x)

Mathematics
1 answer:
viktelen [127]2 years ago
7 0

Answer:

answer fx

Step-by-step explanation:

its fx because it works

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X+8=21 I need helpppp
Mrac [35]
You add 13 and 8 it gets 21 so for X its 13
8 0
4 years ago
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What is the perimeter of the triangle shown on the coordinate plane,to the nearest tenth of a unit ?
ollegr [7]

Answer:

25.6 units

Step-by-step explanation:

From the figure we can infer that our triangle has vertices A = (-5, 4), B = (1, 4), and C = (3, -4).

First thing we are doing is find the lengths of AB, BC, and AC using the distance formula:

d=\sqrt{(x_2-x_1)^{2} +(y_2-y_1)^{2}}

where

(x_1,y_1) are the coordinates of the first point

(x_2,y_2) are the coordinates of the second point

- For AB:

d=\sqrt{[1-(-5)]^{2}+(4-4)^2}

d=\sqrt{(1+5)^{2}+(0)^2}

d=\sqrt{(6)^{2}}

d=6

- For BC:

d=\sqrt{(3-1)^{2} +(-4-4)^{2}}

d=\sqrt{(2)^{2} +(-8)^{2}}

d=\sqrt{4+64}

d=\sqrt{68}

d=8.24

- For AC:

d=\sqrt{[3-(-5)]^{2} +(-4-4)^{2}}

d=\sqrt{(3+5)^{2} +(-8)^{2}}

d=\sqrt{(8)^{2} +64}

d=\sqrt{64+64}

d=\sqrt{128}

d=11.31

Next, now that we have our lengths, we can add them to find the perimeter of our triangle:

p=AB+BC+AC

p=6+8.24+11.31

p=25.55

p=25.6

We can conclude that the perimeter of the triangle shown in the figure is 25.6 units.

6 0
3 years ago
Outcome
Luda [366]

Answer: sorry the answer is not clear.

Step-by-step explanation:

4 0
3 years ago
Describe the slope of the line passing through points A(-2,3) and B(4,-3)
erik [133]

Answer:

0/2 is ZERO is positive

Step-by-step explanation:

6 0
3 years ago
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Can someone explain how we solve this problem
riadik2000 [5.3K]
It is look so x=? so if it was 2 then it would be
2-1 = 2+1
_______          which is wrong so that's how to do it which is x?
2+5 = 2-7 

the answer is 1/7 so ya its D.1/7 :) hope i helped
4 0
3 years ago
Read 2 more answers
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