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VLD [36.1K]
2 years ago
7

PLEASE HELP ASAP!

Chemistry
1 answer:
pychu [463]2 years ago
3 0

V1M1c1 = V2M2c2

29 x 0.26 x 1 = V2 x 0.4 x 2

V2 = 9.425

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A sealed container of nitrogen gas is at 1000.0 kPa pressure and at a temperature of 20.00 °C. The container is left in the sun,
vodka [1.7K]

Answer:

P₂ = 1102 Kpa

Explanation:

Given data:

Initial pressure = 1000.0 Kpa

Initial temperature = 20.0°C

Final temperature = 50.0°C

Final pressure = ?

Solution:

Initial temperature = 20.0°C (20+273 = 293 K)

Final temperature = 50.0°C (50+273 = 323 K)

According to Gay-Lussac Law,

The pressure of given amount of a gas is directly proportional to its temperature at constant volume and number of moles.

Mathematical relationship:

P₁/T₁ = P₂/T₂

Now we will put the values in formula:

1000 Kpa / 293 K = P₂/323 K

P₂ = 1000 Kpa × 323 K / 293 K

P₂ = 323000 Kpa. K /293 K

P₂ = 1102 Kpa

7 0
3 years ago
At the beginning of the reaction: N2 + 3H2 -> 2NH there is 1 mol of N. and 3 moles of H, and at the end of it is present a mi
Nikolay [14]

Answer:

75%

Explanation:

call realistic moles of N2 in the reaction is a

moles of H2 :3a

moles of NH3: 2a

the moles of residual N2 after reaction: 1-a

the moles of residual H2 after react: 3- 3a

the moles of mixture: 2a+1-a+3-3a=2.5

-> a=0.75

H=0.75/1=75%

7 0
3 years ago
Mass is constant regardless of an object’s location, but the weight of the object depends upon
IRISSAK [1]
 <span>It </span>depends on<span> the "</span>mass<span>" of an </span>object<span> and the strength of gravity where ... Just remember that </span>mass is constant<span>, and </span>weight<span> is a force that varies</span>
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3 years ago
What are the H-bonds in Fentanyl, and is it souluable in water please explain yes or no.
Margarita [4]

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5 0
4 years ago
Read 2 more answers
Calculate the amount of HCN that gives the lethal dose in a small laboratory room measuring 12.0 ft×15.0 ft×8.60ft.
Damm [24]

<u>Given:</u>

Dimensions of the room= 12 ft * 15 ft * 8.60 ft

<u>To determine:</u>

The amount of HCN that gives the lethal dose in the room with the given dimensions

<u>Explanation:</u>

As per the World Health Organization, the lethal dose of HCN is around 300 ppm

300 ppm = 300 mg of HCN/ kg of inhaled air

Volume of air = volume of room = 12 * 15 *8.6 = 1548 ft³

Now,  1 ft³ = 28316.8 cm³

Therefore, the calculated volume of air corresponds to:

1548 * 28316.8 = 4.383 * 10⁷ cm3

Density of air (at room temperature 25 C) = 0.00118 g/cm3

Thus mass of air corresponding to the calculated volume is

Mass = Density * volume = 0.00118 g/cm3 * 4.383 * 10⁷ cm3

= 5.172*10⁴ g = 51.72 kg

Lethal amount of HCN corresponding to 51.72 kg of air would be.

= 51.72 kg air* 300 mg of HCN/1 kg air = 15516 mg

Ans: Lethal dose of HCN = 15.5 g

5 0
3 years ago
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