The example of a chemical combination that can also be said to be a synthesis reaction is; 
<h3>What is a synthesis reaction?</h3>
We know that the meaning of the synthesis reaction is quite central as we attempt to answer the question that is lying right before us here. If we are talking about the synthesis reaction then our mind must have to go to the kind of reaction in which there is the combination of two or more so as to produce a single compound.
As we are talking about the synthesis reaction, we would have to look at the reaction that would give rise to a single product as it has been written. Let us also recall that we have been told that the reaction is a oxidation-reduction reaction thus there is a change in oxidation number in the process of the reaction as shown.
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Explanation:
Let us assume that the given data is as follows.
mass of barium acetate = 2.19 g
volume = 150 ml = 0.150 L (as 1 L = 1000 ml)
concentration of the aqueous solution = 0.10 M
Therefore, the reaction equation will be as follows.

Hence, moles of
=
.......... (1)
As, No. of moles =
Hence, moles of
will be calculated as follows.
No. of moles =
=
(molar mass of
is 255.415 g/mol)
= 
Moles of
= 
= 0.01715 mol
Hence, final molarity will be as follows.
Molarity = 
= 
= 0.114 M
Thus, we can conclude that final molarity of barium cation in the solution is 0.114 M.
An electron beam makes the object become larger.
<span>6.03 moles.
1 molecule of butane contains 4 carbon atoms and ten hydrogen atoms.
The molar mass is 4 times the atomic mass of carbon, 12 g/mol, plus 10 times the atomic weight of hydrogen, 1 g/mol.
Molar mass = 4 * 12 g/mol + 10 * 1 g/mol = 58 g/mol.
This means that 1 mole of butane has a mass of 58 g.
To figure out how many moles are in a sample of butane, divide the mass of sample in grams by 58 grams
Number of moles in sample = 350 g / 58 g/mol = 6.03 moles.</span>
D- Physical
Explanation:
A physical property is anything that has characteristics associated with a change in it's chemical composition