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jok3333 [9.3K]
2 years ago
10

I need help with the attached​

Mathematics
1 answer:
Aleksandr-060686 [28]2 years ago
8 0

Answer: super sorry! i have no idea but im sure someone else knows (:

Step-by-step explanation:

sorry

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75,15,3 find the 6th term
Karolina [17]

Answer:

0.024

Step-by-step explanation:

75, 15, 3, ...

Now, let's take a look at thus pattern.

You'll notice how the numbers decrease.

Divide 75 by 5.

We get 15

Divide 15 by 5.

We get 3.

Then we have the pattern now.

3 ÷ 5 = 0.6 (4th term)

0.6 ÷ 5 = 0.12 (5th term)

0 12 ÷ 5 = 0.024 (6th term)

I hope it helps.

8 0
3 years ago
Sean Wrona is the fastest typist in the world and can type an average of about 500 words in three minutes.
VARVARA [1.3K]

Answer:

166.67 is answer of this question

7 0
3 years ago
A = 310 rounded to the nearest 10
GREYUIT [131]

Answer:

a = (rounded) 310

b = (rounded) 66.1

These two were already rounded to their designated rounding value.

a/b = (rounded) 4.69

You round up since the 3rd DP is greater than or equal to 5.

Please mark for Brainliest!!  :D Thank you!!

For any questions, please comment!!

6 0
4 years ago
Which of the following definite integrals could be used to calculate the total area bounded by the graph of y = x^3 – 3x^2 + 2x
castortr0y [4]

Answer: The correct option is second, i.e. ,"2 times the integral from 0 to 1 of the quantity x cubed minus 3 times x squared plus 2 times x, dx".

Explanation:

The given equation is,

y=x^3-3x^2+2x

It can be written as,

f(x)=x^3-3x^2+2x

Find the zeros of the equation. Equation the function equal to 0.

0=x^3-3x^2+2x

x(x^2-3x+2)=0

x(x^2-2x-x+2)=0

x(x-2)(x-1)=0

So, the three zeros are 0, 1 and 2.

The graph of the equation is shown below.

From the given graph it is noticed that the enclosed by the curve and x- axis is lies between 0 to 2, but the area from 0 to 1 lies above the x-axis and area from 1 to 2 lies below the x-axis. So the function will be negative from 1 to 2.

The area enclosed by curve and x-axis is,

A=\int_{0}^{1}f(x)dx+\int_{1}^{2}[-f(x)]dx

A=\int_{0}^{1}f(x)dx-\int_{1}^{2}f(x)dx

From the graph it is noticed that the area from 0 to 1 is symmetric or same as area from 1 to 2. So the total area is the twice of area from 0 to 1.

A=2\int_{0}^{1}f(x)dx

A=2\int_{0}^{1}[x^3-3x^2+2x]dx

Therefore, The correct option is "2 times the integral from 0 to 1 of the quantity x cubed minus 3 times x squared plus 2 times x, dx".

3 0
3 years ago
5. Is the number 0.6 with the line on top rational or irrational?
mafiozo [28]

Answer:

It's a rational number/decimal

Step-by-step explanation:

8 0
3 years ago
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